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The reveal_type in the example below produces no output, since the expression is not type checked:
reveal_type
# mypy: disallow-untyped-calls def f(x): pass y = 1 f(reveal_type(y)) # No output!
I think that this may also result in crashes, at least when calculating code stats.
The text was updated successfully, but these errors were encountered:
Always type check arguments when using --disallow-untyped-calls
9a3cdb7
Fixes #9509.
Always type check arguments when using --disallow-untyped-calls (#9510)
c65c972
498769b
JukkaL
Successfully merging a pull request may close this issue.
The
reveal_type
in the example below produces no output, since the expression is not type checked:I think that this may also result in crashes, at least when calculating code stats.
The text was updated successfully, but these errors were encountered: