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Is it possible to define a protocol for a method? #1040

Answered by Akuli
tobinus asked this question in Q&A
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I'm starting to think that the "callback protocol" approach is not usable for this usecase, because an instance of a class with a __call__ method is not functionally equivalent to a function when assigned as a class attribute.

That's correct. When Python looks up a method from an instance, it calls __get__ to get a method object, which it then __call__()s. If there is no __get__, the object is called as is, without passing self.

Consider this, for example:

>>> class Foo:
...     def method(self):
...             print("hi")
... 
>>> f = Foo()
>>> f.method
<bound method Foo.method of <__main__.Foo object at 0x7f58edb5f310>>
>>> Foo.method
<function Foo.method at 0x7f58edb30790>
>>> Foo.m…

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@Akuli
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Answer selected by tobinus
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