增加连续数字的解析

README.md

@@ -28,6 +28,9 @@ You can use the top-level api:
 ~~~ruby
 ChinseNumber.trans "我有十块钱"
 #=> "我有10块钱"
+
+ChinseNumber.trans "二〇一四年"
+#=> "2014年"
 ~~~
 
 or use the standalone parser:

chinese_number.gemspec

@@ -8,8 +8,8 @@ Gem::Specification.new do |spec|
   spec.version       = ChineseNumber::VERSION
   spec.authors       = ["qhwa"]
   spec.email         = ["qhwa@163.com"]
-  spec.summary       = %q{TODO: Write a short summary. Required.}
-  spec.description   = %q{TODO: Write a longer description. Optional.}
+  spec.summary       = %q{Translate Chinese numbers into Arabic numbers}
+  spec.description   = %q{This ruby gem translate Chinse numbers into Arabic numbers. e.g. “一十” => 10.}
   spec.homepage      = ""
   spec.license       = "MIT"
 

lib/chinese_number/parser.rb

@@ -34,6 +34,14 @@ def self.generate_multipers_map
     TOKEN          = Regexp.new( "[#{(DIGIT_MAP.keys + MULTIPERS.keys).join}]+" )
 
     def parse word
+
+      raise InvalidWord unless word =~ /\A#{TOKEN}\Z/
+
+      # 类似“二零一二” 这种短语，可以直接拼数字返回
+      unless word =~ MULTIPER_TOKEN
+        return word.gsub(/\S/) {|w| DIGIT_MAP[w]}.to_i
+      end
+
       @scanner = StringScanner.new( word )
       parts    = []
 
@@ -83,7 +91,7 @@ def to_i
       end
     end
 
-    class UnexpectToken < RuntimeError
+    class InvalidWord < RuntimeError
     end
 
   end

spec/parser_spec.rb

@@ -6,6 +6,12 @@
     @parser = ChineseNumber::Parser.new
   end
 
+  it '可以解析连续的数字' do
+    test '一二三', 123
+    test '二零一二', 2012
+    test '二〇一二', 2012
+  end
+
   it '可以解析个位数字' do
     test '零', 0
     test '〇', 0
@@ -82,7 +88,7 @@
   it '对于不合法的文字抛出错误' do
     expect {
       @parser.parse('没有数字').should
-    }.to raise_error( ChineseNumber::Parser::UnexpectToken )
+    }.to raise_error( ChineseNumber::Parser::InvalidWord )
   end
 
   def test word, expect_digit