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When I try to parse an N3, I get an error when a literal contains a \t. But
\t is defined to be in N3 strings.
I suspect the failure is in n3proc's unquote:
>>> from rdflib.syntax.parsers.n3p.n3proc import unquote
>>> unquote("\t")
Traceback (most recent call last):
File "", line 1, in
File "build/bdist.linux-i686/egg/rdflib/syntax/parsers/n3p/n3proc.py",
line 85, in unquote
rdflib.syntax.parsers.n3p.n3proc.ParseError: Illegal literal character: '\t'
Comment 1 by eike...@gmail.com
This is actually correct, I believe, since "\t" should be escaped as r"\t". For example unquote(r"\t") will give you
"\t" -- and unquote("\t") (AKA an actual tab character) will give the above error.
In looking into this issue I did notice Literal's n3 method is not correctly escaping "\t". Literal("\t").n3() should be
"\\t" which is the same as r"\t".
Comment 2 by eike...@gmail.com
Comment 3 by gromgull
Eikeon is right - this seem to work fine
{{{
g=rdflib.graph.Graph()
g.parse(StringIO.StringIO(r' "Gunnar\tlikes chese". '),
format="n3")
print g.serialize()
<_4:name>Gunnar likes chese
}}}
The text was updated successfully, but these errors were encountered:
hannes.g...@gmail.com, 2008-01-23T10:32:30.000Z
The text was updated successfully, but these errors were encountered: