#break/return not working inside #regexp

[Lanbosudo]

Like title says, I found that #break/#return doesn't work as intended when used inside #regexp.
Example:

#foreach {{1}{2}{3}{4}{5}{6}} tmp {
    #regexp {"$tmp"} {"5"} {
        #break;
    } {
        #echo $tmp
    }
}

Output is 1 2 3 4 6 instead of 1 2 3 4.

Is this the way #regexp should be working?

Env: Debian in WSL Windows 10
Tintin: 2.02.05

[scandum]

As per #help break

The break command can be used inside the #foreach, #loop, #parse,
#while and #switch statements.

#regex has its own scope so #break and #return won't work within it.

I'll have to rewrite the scripting engine to handle #regex, which probably won't be anytime soon. You can however use:

#foreach {{1}{2}{3}{4}{5}{6}} tmp {
    #regexp {"$tmp"} {"{[^5]}"} {
        #echo $tmp
    };
    #else 
    {
        #break;
    }
}

[Lanbosudo]

As per #help break

The break command can be used inside the #foreach, #loop, #parse,
#while and #switch statements.

#regex has its own scope so #break and #return won't work within it.

I'll have to rewrite the scripting engine to handle #regex, which probably won't be anytime soon. You can however use:

#foreach {{1}{2}{3}{4}{5}{6}} tmp {
    #regexp {"$tmp"} {"{[^5]}"} {
        #echo $tmp
    };
    #else 
    {
        #break;
    }
}

Yeah, sure, that's what i'm doing now. Thanks for the prompt reply~