typescript error with sequelize literal

[fareshan]

This does not work:

const aas = await A.findAll({
      where: Sequelize.literal(
        `id IN (
            SELECT "aaId"
            FROM "Pp"
            WHERE "ppId" = 10
            )
        `,
      ),
    });

The typescript error:

Argument of type '{ where: Literal; }' is not assignable to parameter of type 'FindOptions'.
  Types of property 'where' are incompatible.
    Type 'Literal' is not assignable to type 'WhereAttributeHash | AndOperator | OrOperator | Where | undefined'.
      Type 'Literal' is not assignable to type 'WhereAttributeHash'.
        Index signature is missing in type 'Literal'.ts(2345)

Environment

sequelize-typescript: 1.0.0-beta.3
Dialect:

• mysql
• [ X ] postgres
• sqlite
• mssql
• any
  Dialect library version: pg version 6.4.2
  Database version: 9.6.12
  Sequelize version: 5.8.10
  Node Version: 8.11.4
  OS: macOS 10.14.3
  TypeScript version: 3.4.3 (or 3.3.3 same issue)
  Tested with latest release:
• No
• [ X ] Yes, specify that version: 5.8.10

[leejh3224]

refer to this issue

[fareshan]

@leejh3224 this looks more like a turnaround than a solution

[fareshan]

this issue is fixed with this fix:
https://github.com/sequelize/sequelize/pull/10990

[papb]

Fixed by #10990

(the link by @fareshan above was broken)