utf8ncat - size wraparound bug

[LutzenH]

Hello 👋! I think I found a small bug in utf8ncat when the function is executed with size_t n being 0.
The function will still write all remaining bytes to the dst buffer.

for example:

utf8_int8_t dst[12] = { 'h', 'e', 'l', 'l', 'o', '\0' };
const utf8_int8_t* src = "world";
utf8ncat(dst, src, 0);

// dst will be { 'h', 'e', 'l', 'l', 'o', 'w', 'o', 'r', 'l', 'd', '\0', '\0' };

If I am not mistaken it is because size_t being unsigned which causes the following --n to wraparound:

utf8.h/utf8.h

Line 631 in 89f6a43

} while (('\0' != *src) && (0 != --n));

I presume this is not defined behavior and that this is a bug.

[sheredom]

Good find! Hopefully fixed in #98.