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Rmove RHom
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aisejohan committed May 14, 2024
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Expand Up @@ -7181,9 +7181,9 @@ \section{Cup product}
Here is another way to think of the cup product of $\xi$ and $\eta$.
Namely, we can write
$$
R\Gamma(X, K) = R\Hom_X(\mathcal{O}_X, K)
R\Gamma(X, K) = \Hom_{D(\mathcal{O}_X)}(\mathcal{O}_X, K)
\quad\text{and}\quad
R\Gamma(X, M) = R\Hom_X(\mathcal{O}_X, M)
R\Gamma(X, M) = \Hom_{D(\mathcal{O}_X)}(\mathcal{O}_X, M)
$$
because $\Hom(\mathcal{O}_X, -) = \Gamma(X, -)$.
Thus $\xi$ and $\eta$ are the ``same'' thing as maps
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