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Thanks to both of you
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aisejohan committed Apr 30, 2021
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Expand Up @@ -2092,11 +2092,11 @@ \section{Geometrically connected algebraic spaces}
\end{lemma}

\begin{proof}
Let $y \in |Y|$ be represented by a morphism $\Spec(K) \to Y$ be a morphism
Let $y \in |Y|$ be represented by a morphism $\Spec(K) \to Y$
where $K$ is a field. The fibre of $|X \times_k Y| \to |Y|$ over $y$
is the image of $|Y_K| \to |X \times_k Y|$ by
is the image of $|X_K| \to |X \times_k Y|$ by
Properties of Spaces, Lemma \ref{spaces-properties-lemma-points-cartesian}.
Thus these fibres are connected by our assumption that $Y$ is
Thus these fibres are connected by our assumption that $X$ is
geometrically connected. By
Morphisms of Spaces, Lemma
\ref{spaces-morphisms-lemma-space-over-field-universally-open}
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