Skip to content

Commit

Permalink
Fix error in Lemma 0ANU
Browse files Browse the repository at this point in the history
Thanks to Brian Conrad for pointing this out
http://stacks.math.columbia.edu/tag/0ANU#comment-1973

The mistake was using Lemma 07RD without checking the finiteness
assumption in that lemma. Fixed by replacing property (b) by a stronger
condition where we ask for a confinal system of weak ideals of
definition with the desired property.

Also: added a new lemma which explains that if we work with admissible
topological rings and ideals of definition (in stead of weakly
admissible topological rings and weak ideals of definition), then the
lemma is true as it was formulated before this change...
  • Loading branch information
aisejohan committed May 2, 2016
1 parent eeae2b2 commit a555a1b
Show file tree
Hide file tree
Showing 2 changed files with 57 additions and 12 deletions.
68 changes: 56 additions & 12 deletions restricted.tex
Expand Up @@ -287,13 +287,14 @@ \section{Algebras topologically of finite type}
\item[(a)] $B \to A$ is taut and $B/J \to A/I$ is of finite type for
every weak ideal of definition $J \subset B$ where $I \subset A$ is the
closure of $JA$,
\item[(b)] $B \to A$ is taut and $B/J \to A/I$ is of finite type for
some weak ideal of definition $J \subset B$ with $I \subset A$ the
closure of $JA$,
\item[(b)] $B \to A$ is taut and $B/J_\lambda \to A/I_\lambda$
is of finite type for a cofinal system $(J_\lambda)$
of weak ideals of definition of $B$ where
$I_\lambda \subset A$ is the closure of $J_\lambda A$,
\item[(c)] $B \to A$ is taut and $A$ is topologically of finite
type over $B$,
\item[(d)] $A$ is isomorphic to a quotient of $B\{x_1, \ldots, x_n\}$
by a closed ideal.
\item[(d)] $A$ is isomorphic as a topological $B$-algebra to a quotient of
$B\{x_1, \ldots, x_n\}$ by a closed ideal.
\end{enumerate}
Moreover, these equivalent conditions define a local property,
i.e., they satisfy Formal Spaces, Axioms (\ref{formal-spaces-item-axiom-1}),
Expand All @@ -314,25 +315,28 @@ \section{Algebras topologically of finite type}
$$
such that $A_{n + 1}/J_nA_{n + 1} = A_n$ and such that $A = \lim A_n$ as in
Formal Spaces, Lemma \ref{formal-spaces-lemma-representable-property-rings}.
We may assume $J = J_1$ by replacing $J_1$ by $J_1 + J$ if necessary.
For every $m$ there exists a $\lambda$ such that $J_\lambda \subset J_m$.
Since $B/J_\lambda \to A/I_\lambda$ is of finite type, this implies
that $B/J_m \to A/I_m$ is of finite type.
Let $\alpha_1, \ldots, \alpha_n \in A_1$ be generators of $A_1$ over
$B/J_1 = B/J$. Since $A$ is a countable limit of a system with surjective
$B/J_1$. Since $A$ is a countable limit of a system with surjective
transition maps, we can find $a_1, \ldots, a_n \in A$ mapping to
$\alpha_1, \ldots, \alpha_n$ in $A_1$. By
Remark \ref{remark-universal-property} we find a continuous map
$B\{x_1, \ldots, x_n\} \to A$ mapping $x_i$ to $a_i$. This map
induces surjections $B/J_m[x_1, \ldots, x_n] \to A_m$ by
induces surjections $(B/J_m)[x_1, \ldots, x_n] \to A_m$ by
Algebra, Lemma \ref{algebra-lemma-surjective-mod-locally-nilpotent}.
For $m \geq 1$ we obtain a short exact sequence
$$
0 \to K_m \to B/J_m[x_1, \ldots, x_n] \to A_m \to 0
0 \to K_m \to (B/J_m)[x_1, \ldots, x_n] \to A_m \to 0
$$
The induced transition maps $K_{m + 1} \to K_m$ are surjective because
$A_{m + 1}/J_mA_{m + 1} = A_m$. Hence the inverse limit of these
short exact sequences is exact, see
Algebra, Lemma \ref{algebra-lemma-ML-exact-sequence}.
Since $B\{x_1, \ldots, x_n\} = \lim B/J_m[x_1, \ldots, x_n]$ and $A = \lim A_m$
we conclude that $B\{x_1, \ldots, x_n\} \to A$ is surjective.
Since $B\{x_1, \ldots, x_n\} = \lim (B/J_m)[x_1, \ldots, x_n]$
and $A = \lim A_m$
we conclude that $B\{x_1, \ldots, x_n\} \to A$ is surjective and open.
As $A$ is complete the kernel is a closed ideal. In this way we see that
(a), (b), (c), and (d) are equivalent.

Expand All @@ -346,7 +350,7 @@ \section{Algebras topologically of finite type}
Formal Spaces, Lemma \ref{formal-spaces-lemma-representable-property-rings}
in order to prove Formal Spaces, Axioms (\ref{formal-spaces-item-axiom-1})
and (\ref{formal-spaces-item-axiom-2})
we may assume both $A \to B$ and $(B')^\wedge \to (A')^\wedge$
we may assume both $B \to A$ and $(B')^\wedge \to (A')^\wedge$
are taut. Now pick a weak ideal of definition $J \subset B$. Let
$J' \subset (B')^\wedge$, $I \subset A$, $I' \subset (A')^\wedge$
be the closure of $J(B')^\wedge$, $JA$, $J(A')^\wedge$.
Expand Down Expand Up @@ -377,6 +381,46 @@ \section{Algebras topologically of finite type}
We omit the proof of Formal Spaces, Axiom (\ref{formal-spaces-item-axiom-3}).
\end{proof}

\begin{lemma}
\label{lemma-quotient-restricted-power-series-admissible}
In Lemma \ref{lemma-quotient-restricted-power-series}
if $B$ is admissible (for example adic), then the equivalent conditions
(a) -- (d) are also equivalent to
\begin{enumerate}
\item[(e)] $B \to A$ is taut and $B/J \to A/I$ is of finite type for
some ideal of definition $J \subset B$ where $I \subset A$ is
the closure of $JA$.
\end{enumerate}
\end{lemma}

\begin{proof}
It is enough to show that (e) implies (a). Let $J' \subset B$ be a weak ideal
of definition and let $I' \subset A$ be the closure of $J'A$. We have
to show that $B/J' \to A/I'$ is of finite type. If the corresponding statement
holds for the smaller weak ideal of definition $J'' = J' \cap J$, then it
holds for $J'$. Thus we may assume $J' \subset J$. As $J$ is an ideal
of definition (and not just a weak ideal of definition), we get
$J^n \subset J'$ for some $n \geq 1$. Thus we can consider the
diagram
$$
\xymatrix{
0 \ar[r] & I/I' \ar[r] & A/I' \ar[r] & A/I \ar[r] & 0 \\
0 \ar[r] & J/J' \ar[r] \ar[u] & B/J' \ar[r] \ar[u] & B/J \ar[r] \ar[u] & 0
}
$$
with exact rows. Since $I' \subset A$ is open and since
$I$ is the closure of $J A$ we see that $I/I' = (J/J') \cdot A/I'$.
By assumption we can find a surjection $(B/J)[x_1, \ldots, x_n] \to A/I$.
We can lift this to $(B/J')[x_1, \ldots, x_n] \to A'/I'$.
Because $J/J'$ is a nilpotent ideal, we may apply part (11) of
Algebra, Lemma \ref{algebra-lemma-NAK} to the map of $B/J'$-modules
$$
(B/J')[x_1, \ldots, x_n] \to A'/I'
$$
to see that it is surjective. Thus $A/I'$ is of finite type over $B/J'$
as desired.
\end{proof}

\begin{lemma}
\label{lemma-representable-affine-finite-type}
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of
Expand Down
1 change: 1 addition & 0 deletions tags/tags
Expand Up @@ -15454,3 +15454,4 @@
0CB3,more-morphisms-lemma-nr-minimal-primes
0CB4,more-morphisms-lemma-nr-branches
0CB5,more-morphisms-lemma-nr-branches-fibre
0CB6,restricted-lemma-quotient-restricted-power-series-admissible

0 comments on commit a555a1b

Please sign in to comment.