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Fix erroneous example
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aisejohan committed Apr 29, 2022
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Expand Up @@ -1210,9 +1210,9 @@ \section{Dimension at a point}
Warning: It is {\bf not} the case that $\dim_x(X) = \dim_x(|X|)$
in general. A counter example is the algebraic space $X$ of
Spaces, Example \ref{spaces-example-infinite-product}.
Namely, in this example we have $\dim_x(X) = 0$ and
$\dim_x(|X|) = 1$ (this holds for any $x \in |X|$).
In particular, it also means that the dimension of $X$ (as defined
Namely, let $x \in |X|$ be a point not equal to the generic point $x_0$
of $|X|$. Then we have $\dim_x(X) = 0$ but $\dim_x(|X|) = 1$.
In particular, the dimension of $X$ (as defined
below) is different from the dimension of $|X|$.

\begin{definition}
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