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laurent series Fibonacci generating fuction #21245
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The implementation of the series expansion starts by computing the leading term of the denominator at 1/fi:
This fails because
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Maybe all expand functions can be dispensed with if
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Hi all,
I play little bit with Fibonacci gf.
fi = (1+sp.sqrt(5))/2 # this is singularity of Fib. gf. (inverse of golden ratio)
(1/(1-x-x**2)).series(x,1/fi,2)
and I getThis is clearly not a laurent series in 1/fi and the first therm is /0.
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