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@oscarbenjamin , I thought that extension works only on factoring binomials, not coefficients. Is there any way I can factor x**2+1 into (x-I)(x+I), but leave Ix-1 unchanged? If I add extension=True, then Ix-1 is factored as I(Ix+I).
factor(-exp(x)*tan(pi/7) + 1, extension=True)
Without the
extension
flag everything is OK.The text was updated successfully, but these errors were encountered: