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kernel: grant: do not pass T::default() #2003
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I'm pretty uncertain why this change would actually solve the "grants temporarily take up a ton of stack space" problem.
T::default()
is still going to return a T, which will be its full size and on the stack. Is passing it into thealloc_unowned()
function taking double the size of T on the stack or something?There was a problem hiding this comment.
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Per a slack discussion with bradjc, this change greatly increases the possible size of IPC grants before a kernel stack overflow occurs (previously 364 bytes increases to 2364 bytes). I'm guessing some compiler optimizations are making the magic happen here.
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Right, presumably the compiler can better guess to just allocate the space for the default value directly at
ptr.as_ptr()
as opposed to on the stack first.