lib: Remove Any.hash_code #1999
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Just like equality, the hash_code function should be a type feature and not be defined for Any and inherited. For hash_code to be useful, the following invariant should hold: (hash_code a != hash_code b) || (a = b) So the semantics of hash_code depends on type.equality, so hash_code should be a type feature as well.
maxteufel
approved these changes
Sep 20, 2023
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Just like equality, the hash_code function should be a type feature and not be defined for Any and inherited.
For hash_code to be useful, the following invariant should hold:
So the semantics of
hash_codedepends ontype.equality, sohash_codeshould be a type feature as well.