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Speedup route_search_all ~3x with vectorized updates of next matrix
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Refactor the route_search_all method in RouteChoice to utilize NumPy's vectorized operations and boolean indexing, eliminating nested loops for updating the next matrix. This significantly enhances performance by reducing Python loop overhead in sparse graph computations.

In a real-world road graph with 3275 links and 1552 nodes, it reduced the time route_search_all from ~0.85 seconds to ~0.30 seconds, a ~3x speedup.

Together with the previous commit, it reduced the time route_search_all from ~19 seconds to ~0.3 seconds, a ~60x speedup.
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EwoutH committed Apr 1, 2024
1 parent 1b9df13 commit e93a4ab
Showing 1 changed file with 11 additions and 6 deletions.
17 changes: 11 additions & 6 deletions uxsim/uxsim.py
Original file line number Diff line number Diff line change
Expand Up @@ -992,12 +992,17 @@ def route_search_all(s, infty=np.inf, noise=0):
s.dist, s.pred = dijkstra(csgraph=csr_mat, directed=True, indices=None, return_predecessors=True)

# Directly use the predecessors to update the next matrix for route choice
n_vertices = s.pred.shape[0]
s.next = np.full((n_vertices, n_vertices), -1, dtype=int) # Initialize with -1
for i in range(n_vertices):
for j in range(n_vertices):
if i != j and s.pred[i, j] != -9999:
s.next[i, j] = s.pred[i, j]
# Vectorized update of self.next
n_vertices = self.pred.shape[0]
self.next = np.full((n_vertices, n_vertices), -1, dtype=int) # Initialize with -1

# Vectorized operation to copy `self.pred` into `self.next` where pred != -9999
valid_pred = self.pred != -9999
self.next[valid_pred] = self.pred[valid_pred]

# Correcting diagonal elements if necessary
# This step ensures that diagonal elements, which represent paths from a node to itself, are correctly set to -1.
np.fill_diagonal(self.next, -1)

def route_search_all_old(s, infty=9999999999999999999, noise=0):
"""
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