MultiWayIf formatted with four spaces

[oberblastmeister]

Describe the bug

testing =
  if
    | otherwise -> ()
    | otherwise -> ()
    | otherwise -> ()

gets formatted into this

testing =
  if
      | otherwise -> ()
      | otherwise -> ()
      | otherwise -> ()

Expected behavior
It should not be formatted with four spaces.

Environment

• OS name + version: Arch Linux
• ormolu 0.5.3.0 1b39d94d0c06aa53a577f7e0476695f9e6f5020b using ghc-lib-parser 9.4.3.20221104

[mrkkrp]

There is a reason for this, see #488.

[amesgen]

Yeah, I wonder whether we might want to revisit that, given that we have the same problem with do:

testing = 
  do
    succ
   1

In #707 (comment), we decided that this should be a fixed point, as indenting the bodies of do blocks by 4 spaces to account just for this edge case seems to be more severe than violating our "indentation should be divisible by 2" principle.

From a consistency standpoint, shouldn't we change MultiWayIf to also use only 2 spaces and accept the 1 space indentation if an argument is applied to it? WDYT?

[mitchellwrosen]

From a consistency standpoint, shouldn't we change MultiWayIf to also use only 2 spaces and accept the 1 space indentation if an argument is applied to it? WDYT?

I agree with this. Aside: I have never even seen code that applies the RHS of a multi-way if to an argument; I didn't know it was possible. 😅

[mrkkrp]

Note that if we start using 1 space, then whatever is nested inside that 1-space-indented block is going to be at odd (literally) indentations: 3, 5, etc., and it this kind of code block can be potentially large, which is the worst.

I do understand the consistency argument though.

[amesgen]

Another alternative that would fix this issue and also improve consistency: What about identing do blocks/cases/MultiWayIf with with 4 spaces iff it is the applicand (i.e. f in f a)?

I.e. this would be a fixed point, note how applied do blocks and MultiWayIf are now formatted consistently compared to the current output, and foo1 no longer has odd indentation:

Proposed fixed point	Current output
foo0 = do 2 foo1 = do succ 1 foo2 = if | otherwise -> 2 foo3 = if | otherwise -> succ 1	foo0 = do 2 foo1 = do succ 1 foo2 = if | otherwise -> 2 foo3 = if | otherwise -> succ 1

[mrkkrp]

@amesgen I quite like this idea.