New issue
Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.
By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.
Already on GitHub? Sign in to your account
[Bug Report] onChange for timePicker #5266
Comments
@pwildschut Can you provide a codepen with explanation what and when should happen? |
I have created this to visualize, somehow it looks weird. But functionally it proves my point. https://codepen.io/pwildschut/pen/aRVJaN Apologies for the delayed answer. |
It always emits 00:25 for me, I'd call this a bug. |
It works better if you use v-model, but maybe this behaviour could be fixed too |
jacekkarczmarczyk
added
T: bug
Functionality that does not work as intended/expected
S: has PR
The issue has a pending Pull Request
and removed
pending review
The issue is still pending disposition
labels
Nov 21, 2018
jacekkarczmarczyk
added a commit
that referenced
this issue
Nov 21, 2018
8 tasks
jacekkarczmarczyk
added a commit
that referenced
this issue
Nov 23, 2018
jacekkarczmarczyk
added a commit
that referenced
this issue
Dec 1, 2018
jacekkarczmarczyk
added a commit
that referenced
this issue
Dec 1, 2018
MajesticPotatoe
changed the title
onChange for timePicker
[Bug Report] onChange for timePicker
Dec 7, 2018
This was referenced Jan 1, 2019
1 task
Sign up for free
to subscribe to this conversation on GitHub.
Already have an account?
Sign in.
What problem does this feature solve?
In the case that a variable change is a trigger for other functionality the onInput event generates too much noise. An onChange event would be more reliable
What is your proposed solution?
I have seen in the code that the timePicker is prepared to return the onchange event. it just seems to be returning the input value, so its actually not doing anything :/
The text was updated successfully, but these errors were encountered: