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给你一个数组 orders,表示客户在餐厅中完成的订单,确切地说, orders[i]=[customerNamei,tableNumberi,foodItemi] ,其中 customerNamei 是客户的姓名,tableNumberi 是客户所在餐桌的桌号,而 foodItemi 是客户点的餐品名称。
请你返回该餐厅的 点菜展示表 。在这张表中,表中第一行为标题,其第一列为餐桌桌号 “Table” ,后面每一列都是按字母顺序排列的餐品名称。接下来每一行中的项则表示每张餐桌订购的相应餐品数量,第一列应当填对应的桌号,后面依次填写下单的餐品数量。
注意:客户姓名不是点菜展示表的一部分。此外,表中的数据行应该按餐桌桌号升序排列。
输入:orders = [["David","3","Ceviche"],["Corina","10","Beef Burrito"],["David","3","Fried Chicken"],["Carla","5","Water"],["Carla","5","Ceviche"],["Rous","3","Ceviche"]] 输出:[["Table","Beef Burrito","Ceviche","Fried Chicken","Water"],["3","0","2","1","0"],["5","0","1","0","1"],["10","1","0","0","0"]] 解释: 点菜展示表如下所示: Table,Beef Burrito,Ceviche,Fried Chicken,Water 3 ,0 ,2 ,1 ,0 5 ,0 ,1 ,0 ,1 10 ,1 ,0 ,0 ,0 对于餐桌 3:David 点了 "Ceviche" 和 "Fried Chicken",而 Rous 点了 "Ceviche" 而餐桌 5:Carla 点了 "Water" 和 "Ceviche" 餐桌 10:Corina 点了 "Beef Burrito"
输入:orders = [["James","12","Fried Chicken"],["Ratesh","12","Fried Chicken"],["Amadeus","12","Fried Chicken"],["Adam","1","Canadian Waffles"],["Brianna","1","Canadian Waffles"]] 输出:[["Table","Canadian Waffles","Fried Chicken"],["1","2","0"],["12","0","3"]] 解释: 对于餐桌 1:Adam 和 Brianna 都点了 "Canadian Waffles" 而餐桌 12:James, Ratesh 和 Amadeus 都点了 "Fried Chicken"
输入:orders = [["Laura","2","Bean Burrito"],["Jhon","2","Beef Burrito"],["Melissa","2","Soda"]] 输出:[["Table","Bean Burrito","Beef Burrito","Soda"],["2","1","1","1"]]
来源:力扣(LeetCode) 链接:https://leetcode-cn.com/problems/display-table-of-food-orders-in-a-restaurant 著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。
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go语言的map没有php的数据方便,哈哈,但是要注意返回类型,必须是string
class Solution { /** * @param String[][] $orders * @return String[][] */ function displayTable($orders) { $ret = [['Table']]; // 保存所有的餐品 $foods = []; // 保存所有的桌号 $tables = []; // 生成一个嵌套数据,数据key是桌号,value是一个数组,value的key是餐品名称,value的value是餐品数量 $cntByFoodByTable = []; foreach ($orders as $order) { if (isset($cntByFoodByTable[$order[1]])) { $cntByFood = $cntByFoodByTable[$order[1]]; if (isset($cntByFood[$order[2]])) { $cntByFood[$order[2]] = $cntByFood[$order[2]] + 1; } else { $cntByFood[$order[2]] = 1; } $cntByFoodByTable[$order[1]] = $cntByFood; } else { $cntByFoodByTable[$order[1]][$order[2]] = 1; } $foods[] = $order[2]; $tables[] = $order[1]; } $foods = array_unique($foods); sort($foods); $tables = array_unique($tables); sort($tables); foreach ($foods as $food) { $ret[0][] = $food; } foreach ($tables as $table) { $row = []; $row[] = $table; foreach ($foods as $food) { $row[] = isset($cntByFoodByTable[$table][$food]) ? $cntByFoodByTable[$table][$food] : 0; } $ret[] = $row; } return $ret; } }
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给你一个数组 orders,表示客户在餐厅中完成的订单,确切地说, orders[i]=[customerNamei,tableNumberi,foodItemi] ,其中 customerNamei 是客户的姓名,tableNumberi 是客户所在餐桌的桌号,而 foodItemi 是客户点的餐品名称。
请你返回该餐厅的 点菜展示表 。在这张表中,表中第一行为标题,其第一列为餐桌桌号 “Table” ,后面每一列都是按字母顺序排列的餐品名称。接下来每一行中的项则表示每张餐桌订购的相应餐品数量,第一列应当填对应的桌号,后面依次填写下单的餐品数量。
注意:客户姓名不是点菜展示表的一部分。此外,表中的数据行应该按餐桌桌号升序排列。
示例 1:
示例 2:
示例 3:
提示:
来源:力扣(LeetCode)
链接:https://leetcode-cn.com/problems/display-table-of-food-orders-in-a-restaurant
著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。
The text was updated successfully, but these errors were encountered: