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例题26 约瑟夫问题的变形 约瑟夫原版问题答案为:f(n)=(f(n-1)+k)%n 该变形问题答案为:(m-k+1+f(n))%n 请问m-k+1是为什么呢?怎么变的? 谢谢!
Original issue reported on code.google.com by ysq.sinc...@gmail.com on 14 Feb 2014 at 6:45
ysq.sinc...@gmail.com
The text was updated successfully, but these errors were encountered:
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Original issue reported on code.google.com by
ysq.sinc...@gmail.com
on 14 Feb 2014 at 6:45The text was updated successfully, but these errors were encountered: