when process parameters, "self" can't be ModuleType #86
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eg:
=====a.py======
import b.c
b.c.gf("eeeeeeeeeee")
=====b\c.py=====
def gf(param):
pass
Here b.c is package name, not class name
yinwang0
reviewed
Mar 19, 2017
| @@ -1098,7 +1098,7 @@ public Type apply(@NotNull FunType func, | |||
| } | |||
| } else { | |||
| // usual method | |||
| if (selfType != null) { | |||
| if (selfType != null && !(selfType instanceof ModuleType)) { | |||
There was a problem hiding this comment.
This is not the right place to check though. selfType should not be set at all here for package name. Need to find somewhere earlier than this.
|
Please fix it, I am not familiar with it. |
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eg:
=====a.py======
import b.c
b.c.gf("eeeeeeeeeee")
=====b\c.py=====
def gf(param):
pass
Here b.c is package name, not class name