移动零

[yoluxi]

给定一个数组 nums，编写一个函数将所有 0 移动到数组的末尾，同时保持非零元素的相对顺序。

示例:

输入: [0,1,0,3,12] 输出: [1,3,12,0,0]

说明:

1. 必须在原数组上操作，不能拷贝额外的数组。
2. 尽量减少操作次数

[yoluxi]

var moveZeroes = function(nums) {
   return nums.reduce((previousValue, currentdValue, currentIndex, arr) => {
        if (currentdValue === 0) {
            previousValue.splice(currentIndex, 1)
            previousValue.push(0)
        }
        return previousValue
    }, nums) 
}

[yoluxi]

var moveZeroes = function(nums) {
    let i = 0;
    let boundary = nums.length
    for ( ; i < boundary; i++) {
        if (nums[i] === 0) {
            nums.splice(i, 1)
            nums.push(0)
            --i
            --boundary
        }
    }
};

[yoluxi]

var moveZeroes = function(nums) {
   return nums.reduce((previousValue, currentdValue, currentIndex, arr) => {
        if (currentdValue === 0) {
            previousValue.splice(currentIndex, 1)
            previousValue.push(0)
        }
        return previousValue
    }, nums) 
}

[0, 0, 0, 3, 12] => [ 0, 3, 12, 0, 0 ]

[yoluxi]

 let i = -1;
 let j = 0;
 let boundary = nums.length
  while ( j < boundary ) {
        if (nums[j] !== 0) {
            nums[++i] = nums[j]
        }
        j++
    }
     for ( i += 1; i < boundary; i++ ) {
        nums[i] = 0
    }