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fix api doc generate bug
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Wei Zhuo committed Jan 3, 2016
1 parent 3f019db commit 5db081c
Showing 1 changed file with 5 additions and 5 deletions.
10 changes: 5 additions & 5 deletions docs/api_datastructures.md
Original file line number Diff line number Diff line change
Expand Up @@ -64,7 +64,7 @@ attributes default to an empty string.

Return a (possibly empty) list of values for a key.

##def **pop**(key, default=<object object at 0x109baf040>)
##def **pop**(key, default=object())

D.pop(k[,d]) -> v, remove specified key and return the corresponding value.
If key is not found, d is returned if given, otherwise KeyError is raised.
Expand Down Expand Up @@ -205,7 +205,7 @@ If E present and has a .keys() method, does: for k in E: D[k] = E[k]
If E present and lacks .keys() method, does: for (k, v) in E: D[k] = v
In either case, this is followed by: for k, v in F.items(): D[k] = v

##def **pop**(key, default=<object object at 0x109baf040>)
##def **pop**(key, default=object())

D.pop(k[,d]) -> v, remove specified key and return the corresponding value.
If key is not found, d is returned if given, otherwise KeyError is raised.
Expand Down Expand Up @@ -258,7 +258,7 @@ as a 2-tuple; but raise KeyError if D is empty.
##def **append**(key, value)


#class HeaderProperty(name, reader=None, writer=<type 'str'>, default='')
#class HeaderProperty(name, reader=None, writer=str, default='')



Expand Down Expand Up @@ -328,7 +328,7 @@ If E present and has a .keys() method, does: for k in E: D[k] = E[k]
If E present and lacks .keys() method, does: for (k, v) in E: D[k] = v
In either case, this is followed by: for k, v in F.items(): D[k] = v

##def **pop**(key, default=<object object at 0x109baf040>)
##def **pop**(key, default=object())

D.pop(k[,d]) -> v, remove specified key and return the corresponding value.
If key is not found, d is returned if given, otherwise KeyError is raised.
Expand Down Expand Up @@ -433,7 +433,7 @@ If E present and has a .keys() method, does: for k in E: D[k] = E[k]
If E present and lacks .keys() method, does: for (k, v) in E: D[k] = v
In either case, this is followed by: for k, v in F.items(): D[k] = v

##def **pop**(key, default=<object object at 0x109baf040>)
##def **pop**(key, default=object())

D.pop(k[,d]) -> v, remove specified key and return the corresponding value.
If key is not found, d is returned if given, otherwise KeyError is raised.
Expand Down

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