Student Shuffle Algorithim

Year 1 Semester 1 C++ project. (Gender Sorting algorithm)

Problem Statement

The current Computer Science freshmen are in three groups, A, B and C respectively. The gender ratios in these groups are as shown below.

ICS Group	Male	Female
ICS A	19	11
ICS B	16	12
ICS C	36	19
Totals	71	42

Assuming the Faculty has decided to merge the three groups into two, balancing the gender ratios as shown below. Develop a perfect shuffle algorithm (coded) that will give the output in the table below.

ICS Group	Male	Female
ICS A	36	21
ICS B	35	21
Totals	71	42

Prerequisites

1. Objects and Classes
2. STL library (vectors)

Test it out

1. clone repository
2. locate Release folder
3. run studentSystem.exe

Project Oveview

Objects

Students

Attributes

1. surname
2. Name
3. Admission number
4. Gender

Methods

1.Create

Shuffle Algorithim

Vectors

1. student list
2. A_students
3. B_students

Workflow

1. First, files are read from file (one at a time) and stored into a vector student list

2. student list is split into two separate vectors boys and girls

3. push boy ( n ) from boys to A_students and boy ( n + 1 ) from boys to B_students

4. push girl ( n ) from girls to A_students and girl ( n + 1 ) from girls to B_students

5. print A_students vector to B_list.csv

6. print B_students vector to A_list.csv

Code samples

// split student list to boys and girls

for (unsigned int i = 0; i < student_list.size(); i++){
   if (student_list.at(i).gender == "M"){
      boys.push_back(student_list.at(i));
   } else {
      girls.push_back(student_list)
   }
}

//push female(n) to A female (n+1) to B

div = girls.size() % 2;  
for (unsigned int i = 0; i<girls.size()-1; i+=2) {
 A_students.push_back(girls.at(i));
 B_students.push_back(girls.at(i + 1));
 
 if (div > 0 && i == girls.size() - 3) {
  A_students.push_back(girls.at(i + 2));
 }
}

// printing B students to listA

std::ofstream outFileA;

outFileA.open("listA.csv");
 for (unsigned int i = 0; i < listB.size(); i++) {
  outFileA <<listB.at(i).numbr<<","
           <<listB.at(i).surname<<" "
           <<listB.at(i).name<<","
           <<listB.at(i).gender
           <<std::endl;
 }
outFileA.close();