Skip to content

Commit

Permalink
Merge pull request #7 from n04hk/master
Browse files Browse the repository at this point in the history
Kleine Korrekturen
  • Loading branch information
n04hk authored Mar 1, 2020
2 parents 3cd581b + bacedc5 commit 59308d1
Show file tree
Hide file tree
Showing 3 changed files with 4 additions and 4 deletions.
2 changes: 1 addition & 1 deletion sections/Quantization.tex
Original file line number Diff line number Diff line change
Expand Up @@ -56,7 +56,7 @@ \subsection{Oversampling and noise shaping\buchSeite{66-70}}

\vspace{0.2cm}
\begin{minipage}{0.3\textwidth}
Oversampled quantization noise power, \textbf{whitout noise shaping.}
Oversampled quantization noise power, \textbf{without noise shaping.}

\includegraphics[width=\textwidth]{./picture/no_noise_shaping}
\end{minipage}
Expand Down
4 changes: 2 additions & 2 deletions sections/SamplingReconstruction.tex
Original file line number Diff line number Diff line change
Expand Up @@ -118,12 +118,12 @@ \subsubsection{Ideal reconstructor \buchSeite{43}}


\subsubsection{Staircase reconstructor \buchSeite{45}}
\begin{tabular}{p{8cm}}
\begin{tabular}{p{8.2cm}}
$h(t) = u(t) - u(t-T) = \left\lbrace \begin{matrix}
1 & 0\leq t \leq T \\
0 & else
\end{matrix}\right.$ \\
$H(f) = \dfrac{1}{2\pi j f}(1-e^{-2\pi f T}) = T \cdot \dfrac{\sin(\pi f T)}{\pi f T}\cdot e^{-\pi j f T}$
$H(f) = \dfrac{1}{2\pi j f}(1-e^{-2\pi j f T}) = T \cdot \dfrac{\sin(\pi f T)}{\pi f T}\cdot e^{-\pi j f T}$
\end{tabular}
\begin{minipage}{10cm}
\includegraphics[width=10cm]{./picture/compOfDSPSystem}
Expand Down
2 changes: 1 addition & 1 deletion sections/ZTransform.tex
Original file line number Diff line number Diff line change
Expand Up @@ -180,7 +180,7 @@ \subsection{Inverse z-Transform\buchSeite{202-204}}
\sqrt[n]{1} &= e^{j\cdot 2\pi \frac{k}{n}} \quad k \in [1,n] && && \notag
\end{align}

\textbf{Compley valued poles:}
\textbf{Complex valued poles:}
$(1-ae^{j\omega}z^{-1})(1-ae^{-j\omega}z^{-1}) = 1 - 2a\cos(\omega)z^{-1}+a^2z^{-2}$


0 comments on commit 59308d1

Please sign in to comment.