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Faster final exponentiation for BLS12 #211

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merged 12 commits into from
Mar 17, 2021
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@Pratyush Pratyush commented Feb 6, 2021

Description

Implements the faster final exponentiation from https://eprint.iacr.org/2020/875.pdf. In my local benchmarks, this speeds up final exponentiation by ~2%


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Pratyush commented Feb 6, 2021

cc @yelhousni this is adapted from your code

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This is ready for a final review + merge

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@mratsim mratsim left a comment

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I would introduce out-of-place pow_by_x functions.

Also I don't see you using the x/2 trick which also exists in the 2016 paper, a cyclotomic is an interesting saving.

For reference this is my implementation: https://github.com/mratsim/constantine/blob/5806cc46387752d4d011ba663eca0766ff4561e4/constantine/pairing/pairing_bls12.nim#L116-L147

// t[1].Mul(&t[1], &t[2])
y1 *= y2;
// t[2].Expt(&t[1])
y2 = Self::exp_by_x(y1);
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I would be wary if copies of Fp12 elements, in my experience the compiler produce a bench of movaps, movups instructions, you might want an out-of-place pow_by_x

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@Pratyush Pratyush Mar 8, 2021

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To clarify, you mean that exp_by_x should take y1 by reference? Or do you mean that it should mutate y2 in place?

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@mratsim mratsim Mar 10, 2021

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I mean mutate y2 in-place. Does Rust take large stack parameter by reference by default? If not it's needed as well but given that Option and Result work well in Rust I assume it does the right thing.

// t[2].Expt(&t[0])
y2 = Self::exp_by_x(y0);
// t[0].FrobeniusSquare(&t[1])
y0 = y1;
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Ditto for the copy here

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Hm how do I avoid the copy of y1 here?

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@mratsim mratsim Mar 10, 2021

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This is how I did it

  # (x+p)
  v1.pow_x(v0)                 # v1 = f^((x-1)².x)
  v0.frobenius_map(v0)         # v0 = f^((x-1)².p)
  v0 *= v1                     # v0 = f^((x-1)².(x+p))

  # + 3
  f *= v2                      # f = f³

  # (x²+p²−1)
  v2.pow_x(v0, invert = false)
  v1.pow_x(v2, invert = false) # v1 = f^((x-1)².(x+p).x²)
  v2.frobenius_map(v0, 2)      # v2 = f^((x-1)².(x+p).p²)
  v0.cyclotomic_inv()          # v0 = f^((x-1)².(x+p).-1)
  v0 *= v1                     # v0 = f^((x-1)².(x+p).(x²-1))
  v0 *= v2                     # v0 = f^((x-1)².(x+p).(x²+p²-1))

  # (x−1)².(x+p).(x²+p²−1) + 3
  f *= v0

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@ValarDragon ValarDragon left a comment

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This LGTM!

Should we leave todo's in the code / or generally usage of fp12 regarding the copies?

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Pushed some changes which optimize the copying behaviour; this improves the performance by another 2%, for an overall 4% improvement.

@Pratyush Pratyush changed the title New final exp for BLS12 Faster final exponentiation for BLS12 Mar 17, 2021
@Pratyush Pratyush merged commit 4e316d1 into master Mar 17, 2021
@Pratyush Pratyush deleted the faster-bls12-final-exp branch March 17, 2021 15:28
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3 participants