请问如何处理嵌套资源呢？

[dearbird]

我能想到的一个办法是转成查询参数，如
/users/:id/devices => /devices?id=###

[caoym]

可以这么写
@route({"GET","\users*\devices "})
@param({"id", "$.path[1]"}) //$.path是一个数组，对应url path中的每级目录

2016-04-05 18:14 GMT+08:00 dearbird notifications@github.com:

我能想到的一个办法是转成查询参数，如
/users/:id/devices => /devices?id=###

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#3

[caoym]

/**
_@route({"GET","\users_\devices "})
*@param({"id", "$.path[1]"}) //$.path是一个数组，对应url path中的每级目录,
如当前的内容是[users,id,devices]
*/
public function getDevices($id){
....
}

2016-04-06 9:29 GMT+08:00 曹阳敏 caoyangmin@gmail.com:

可以这么写
@route({"GET","\users*\devices "})
@param({"id", "$.path[1]"}) //$.path是一个数组，对应url path中的每级目录

2016-04-05 18:14 GMT+08:00 dearbird notifications@github.com:

我能想到的一个办法是转成查询参数，如
/users/:id/devices => /devices?id=###

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You are receiving this because you are subscribed to this thread.
Reply to this email directly or view it on GitHub
#3

[dearbird]

Perfect, Thanks a lot.