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[krilovskiy]

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• I have read and accepted the contributing guidelines.

How did you create the site?

Generated from chirpy-starter

Description

Hello. I'v successfully deployed blog to github pages but when I'm trying to share post in telegram from here, i'v got link like this
https://t.me/share/url?url=%2Fposts%2Fmethods-on-t%2F&text=%D0%9E%D0%B1%D1%8A%D1%8F%D0%B2%D0%BB%D0%B5%D0%BD%D0%B8%D0%B5%20%D0%BC%D0%B5%D1%82%D0%BE%D0%B4%D0%BE%D0%B2%20%D1%83%20%D1%82%D0%B8%D0%BF%D0%B0%20T%20%D0%B8%D0%BB%D0%B8%20*T%20-%20%D0%92%D0%BB%D0%B0%D0%B4%20%D0%9A%D1%80%D1%8B%D0%BB%D0%BE%D0%B2%D1%81%D0%BA%D0%B8%D0%B9

url parameter is broken. How can i fix this?

Operations you have already tried

I'v uncommented telegram share params

platforms:
  - type: Telegram
    icon: "fab fa-telegram"
    link: "https://t.me/share/url?url=URL&text=TITLE"

  - type: Twitter
    icon: "fa-brands fa-square-x-twitter"
    link: "https://twitter.com/intent/tweet?text=TITLE&url=URL"

  - type: Facebook
    icon: "fab fa-facebook-square"
    link: "https://www.facebook.com/sharer/sharer.php?title=TITLE&u=URL"

  - type: Linkedin
    icon: "fab fa-linkedin"
    link: "https://www.linkedin.com/sharing/share-offsite/?url=URL"

Anything else?

No response

[chuckhoupt]

I think you probably need to set the url: parameter in _config.yml so that Jekyll knows the site's full name. I.e.:

url: "https://krilovskiy.com/"

[krilovskiy]

Thx, very useful, sharing works now.

From config details:

# Fill in the protocol & hostname for your site.
# e.g. 'https://username.github.io', note that it does not end with a '/'.

so we need to write

url: "https://krilovskiy.com"

If no, we will get something like this link https://krilovskiy.com//posts/empty-struct/