fix Issue 19136 - is expressions don't work as documented #13387
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Before this patch,
is ( Type Identifier : TypeSpecialization )
expressions would evaluate to true with basic types, like this:..and many more - you can replace the two types inside the isExpression however you like; the only cases where this would correctly evaluate to false seem to be when one of the types is
void
orType
has a size strictly bigger thanTypeSpecialization
.This fix makes it so that, as per spec, if both
Type
andTypeSpecialization
are basic types, the isExpressions defined like above will evaluate to false if the types are not identical.