How to achieve/measure a temperature step in a material? (Material ignition?) #12971
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Hello everyone, &HEAD CHID='28'/ &TIME T_END=800.0/ &DUMP DT_RESTART=300.0, DT_SL3D=0.25/ &MESH ID='Mesh01', IJK=40,40,40, XB=-1.0,1.0,-1.0,1.0,0.0,2.0/ &SPEC ID='PROPANE'/ &REAC ID='FDS6 METHANE',
&DEVC ID='SOLID101', QUANTITY='ADIABATIC SURFACE TEMPERATURE', XYZ=0.0,0.0,0.7, IOR=3/ &DEVC ID='SOLID10', DEPTH=0.4, QUANTITY='INSIDE WALL TEMPERATURE', XYZ=0.0,0.0,0.3, IOR=-3/ &DEVC ID='SOLID11', QUANTITY='INSIDE WALL TEMPERATURE', XYZ=0.0,0.0,0.3, IOR=-3/ &DEVC ID='SOLID2', DEPTH=0.399, QUANTITY='INSIDE WALL TEMPERATURE', XYZ=-0.199,-0.199,0.3, IOR=-3/ &DEVC ID='SOLID6', DEPTH=1.0E-3, QUANTITY='INSIDE WALL TEMPERATURE', XYZ=-0.199,-0.199,0.3, IOR=-3/ &DEVC ID='SOLID3', DEPTH=0.399, QUANTITY='INSIDE WALL TEMPERATURE', XYZ=0.199,-0.199,0.3, IOR=-3/ &DEVC ID='SOLID7', DEPTH=1.0E-3, QUANTITY='INSIDE WALL TEMPERATURE', XYZ=0.199,-0.199,0.3, IOR=-3/ &DEVC ID='SOLID8', DEPTH=1.0E-3, QUANTITY='INSIDE WALL TEMPERATURE', XYZ=0.199,0.199,0.3, IOR=-3/ &DEVC ID='SOLID4', DEPTH=0.399, QUANTITY='INSIDE WALL TEMPERATURE', XYZ=0.199,0.199,0.3, IOR=-3/ &DEVC ID='SOLID9', DEPTH=1.0E-3, QUANTITY='INSIDE WALL TEMPERATURE', XYZ=-0.199,0.199,0.3, IOR=-3/ &DEVC ID='SOLID5', DEPTH=0.399, QUANTITY='INSIDE WALL TEMPERATURE', XYZ=-0.199,0.199,0.3, IOR=-3/ &DEVC ID='SOLID111', QUANTITY='ADIABATIC SURFACE TEMPERATURE', XYZ=0.0,0.0,0.3, IOR=-3/ &MATL ID='1',
&SURF ID='1',
&SURF ID='burner',
&OBST ID='Obstruction', XB=-0.2,0.2,-0.2,0.2,0.3,0.7, SURF_ID='1'/ &VENT ID='Mesh Vent: Mesh01 [XMAX]', SURF_ID='OPEN', XB=1.0,1.0,-1.0,1.0,0.0,2.0/ &VENT ID='Mesh Vent: Mesh01 [XMIN]', SURF_ID='OPEN', XB=-1.0,-1.0,-1.0,1.0,0.0,2.0/ &VENT ID='Mesh Vent: Mesh01 [YMAX]', SURF_ID='OPEN', XB=-1.0,1.0,1.0,1.0,0.0,2.0/ &VENT ID='Mesh Vent: Mesh01 [YMIN]', SURF_ID='OPEN', XB=-1.0,1.0,-1.0,-1.0,0.0,2.0/ &VENT ID='Mesh Vent: Mesh01 [ZMAX]', SURF_ID='OPEN', XB=-1.0,1.0,-1.0,1.0,2.0,2.0/ &VENT ID='Vent01', SURF_ID='burner', XB=-0.5,0.5,-0.5,0.5,1.0E-3,1.0E-3/ &BNDF QUANTITY='ADIABATIC SURFACE TEMPERATURE'/ &BNDF QUANTITY='BACK WALL TEMPERATURE'/ &BNDF QUANTITY='GAS TEMPERATURE'/ &BNDF QUANTITY='NET HEAT FLUX'/ &BNDF QUANTITY='WALL TEMPERATURE'/ &SLCF QUANTITY='TEMPERATURE', ID='1', PBX=0.0/ &SLCF QUANTITY='TEMPERATURE', ID='2', PBY=0.0/ &TAIL / |
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Replies: 3 comments 9 replies
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Your combustion REAC uses METHANE, but you have defined your MATL to release PROPANE. |
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Hi, my friend! As u say, the values of my materials are wrong. And I have corrected them as below. However, I still can't get a temperature jump. In my mind, when explosives are thermally decomposed, they are violently exothermic, which leads to a sharp increase in temperature. &MATL ID='1', |
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sorry for the preview picture, I have attached a new one. Do you think it is possible to measure the temperature profile in FDS as shown? It should be the curve of an explosive igniting and decomposing, with a violent exotherm. |
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I have no idea what exaclty is being plotted or what the source of that data is.
Explosive materials do not generate heat solely by decomposing into a gas that burns outside the explosive material. Energy is released in the decomposition process itself. In a detonation the temperature rise is not primarily due to conduction but rather pressure shock. FDS is a low Mach number code that is not going to model the pressure compoment of the decomposition.