Don't use "echo -n" in shell scripts

The standard says:

If the first operand is -n, or if any of the operands contain a
backslash ( '\' ) character, the results are implementation-defined.

On OS X it simply prints the "-n" string and everything which follows,
including the newline.

Use printf instead.

m4/geany-status.m4

@@ -27,7 +27,7 @@ EOF
 	# Print a nice top bar
 	# description + ' : ' + value
 	total=`expr $dlen + 3 + $vlen`
-	for i in `seq 1 $total`; do echo -n '-'; done
+	for i in `seq 1 $total`; do printf '-'; done
 	echo
 
 	# And print the actual content

po/intl_stats.sh

@@ -92,7 +92,7 @@ else
    do
      # maybe the regexp can be optimized, regexps are not my best friends
      creationdate=`grep "PO-Revision-Date:" po/$lang.po | sed 's/.*: \([0-9]\{4\}-[0-9]\{2\}-[0-9]\{2\} [0-9]\{2\}:[0-9]\{2\}[+|-][0-9]\{4\}\).*/\1/'`
-     echo -n $eswitch $lang"\t("$creationdate"):\t"
+     printf "%s %s\t(%s):\t" "$eswitch" "$lang" "$creationdate"
      msgfmt --check --statistics po/$lang.po;
    done
 fi