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gebner committed Jan 18, 2012
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Expand Up @@ -182,7 +182,7 @@ \subsection{Laufzeit versus Toleranz}

\subsection{Fehler versus Toleranz}

Wir berechnen das Integral \(\int_{[0,1]^2} \exp(2x+3y) \mathrm d(x,y) = \frac
Wir berechnen das Integral \(\int_{[0,1]^2} \exp(2x+3y)\; \mathrm d(x,y) = \frac
1 6 (e^2-1) (e^3-1) \) und betrachten den relativen Fehler mit kleiner
werdender Toleranz.

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