103. Binary Tree Zigzag Level Order Traversal #35
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nodchip
reviewed
Feb 27, 2024
| return [] | ||
| nodes = [root] | ||
| level = 0 | ||
| ans = [] |
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ans について、プログラム中で何を表しているかを表す単語にした方が良いと思います。自分なら order とつけますが、もう少し良い名前があるかもしれません。
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ありがとうございます。命名サボってしまいました。
| node = nodes[i] | ||
| values.append(node.val) | ||
| first, second = access_orders[level % 2] | ||
| first_node = getattr(node, first) |
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リフレクション的な機能は極力使用しないほうが良いと思います。理由は、コンパイル時の静的な解析でエラーを特定することが難しくなる場合があるためです。
| nodes_ordered = [] | ||
| zigzag_order_nodes_by_level(root, 1) | ||
| # dequeのlistになっているのでlistに変換する | ||
| ans = [] |
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return [list(nodes) for nodes in nodes_ordered]
と掛けなくはないのですが、少し指しすぎかもしれません。
実際の現場においては、単純な内包表記であれば、読みやすさを考慮したうえで使用しても大丈夫だと思います。
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https://leetcode.com/problems/binary-tree-zigzag-level-order-traversal/