Lambda expression generates error

[gratefulfrog]

I have come across this strange bug:

def setup():
    f = lambda x: print(x)
    f(12)

results in this error referring to the line with the lambda
processing.app.SketchException: Maybe there's an unclosed paren or quote mark somewhere before this line?

But this work-around runs ok:

def setup():
    f = lambda x: p(x)
    f(12)

def p(x):
    print(x)

Both work in python3.

As you can see, I'm working in processing.py all day every day!
Ciao,
Bob

[jdf]

Python Mode is Python 2.7, not Python 3.

[gratefulfrog]

oh, sorry...

On Fri, May 13, 2016 at 3:45 PM, Jonathan Feinberg <notifications@github.com

wrote:

Closed #162 #162.

—
You are receiving this because you authored the thread.
Reply to this email directly or view it on GitHub
#162 (comment)