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baseDao

java lambda to static expressionTree to SQL

基于java lambda表达式的orm框架，现仅支持mysql

需要jdk8

欢迎使用，点star，issue，谢谢喵

maven

<dependency>
    <groupId>io.github.kiryu1223</groupId>
    <artifactId>baseDao</artifactId>
    <version>1.0.10</version>
</dependency>

how to start

1.添加maven依赖,并且在共享构建过程VM选项中添加

-Djps.track.ap.dependencies=false

2.添加配置类

@Configuration
public class baseDaoConfig
{
    @Bean
    public BaseDao baseDao(DataSource dataSource)
    {
        return new BaseDao(dataSource, DataBase.Type.Mysql);
    }
}

3.使用idea连接数据库并右键生成持久化映射

4.为你需要使用类添加@Resolve或@Dao注解 不再需要

@SpringBootTest
class HelloDockerApplicationTests
{
    @Autowired
    BaseDao bd;

    @Test
    void contextLoads()
    {
        bd.query(BookInfo.class)
                .where(a -> 1 == 1)
                .select(a -> a)
                .toListAndThen(r -> System.out.println(r));

        //Sql: select a.* from `book_info` as a where ? = ? 
        //values: [1, 1]
    }
}

5.项目 启动！

查询(query)

query中的sql拼接顺序为链式调用的顺序，以select为结尾，比如

baseDao.query(user.class)
       .leftJoin(book.class).on((a,b) -> a.getId == b.getId)
       .where((a,b) -> a.getCode == 1669)
       .orderBy((a,b) -> b.getId)
       .take(50)
       .select((a,b)-> (MyType) new MyType(){{
                setCode(a.getCode);
                setName(b.getName);
        }});

会变成

select a.code,b.name from user as a left join book as b on a.id = b.id where a.code = 1669 order by b.id limit 50 

---

1.query

返回查询pojo类所对应的表的行为，基本上等同于mybatis返回一个sqlsession

baseDao.query(user.class);

等同于

select a.* from user as a

---

2.select

设置select选择的数据库字段与java返回类型，可以选择三种返回方式

• 直接返回查询的pojo类

baseDao.query(user.class).select(a->a);

等同于

select a.* from user as a

• 返回单个数据库字段 暂时不再支持

等同于

• 返回自己定义的新对象

baseDao.query(user.class)
        .select(a-> (MyType) new MyType(){{
            setId(a.getId);
            setName(a.getName);
        }});

等同于

 select a.id,a.name from user as a

---

3.where

查询条件，可以与数据库相关也可以无关（理论上什么都可以写）

baseDao.query(user.class)
        .where(a->a.getName().contains("kiryu"));

等同于

select a.* from user as a where a.id like "%kiryu%"

---

4.innerJoin,leftJoin,rightJoin,fullJoin

选择连表

baseDao.query(user.class)
        .leftJoin(book.class)
        .select((a,b)->b);

等同于

select b.* from user as a left join book as b

---

5.on

连表时的on条件

baseDao.query(user.class)
        .leftJoin(book.class).on((a,b) -> a.getId == b.getId)
        .select((a,b)->b);

等同于

select b.* from user as a left join book as b on a.id = b.id

---

6.orderBy,descOrderBy

根据选择的字段在数据库排序

baseDao.query(user.class)
        .orderBy(a->a.getid());

等同于

select a.* from user as a order by a.id

---

7.take,skip

获取xx跳过xx，等同于mysql中的limit和offset

baseDao.query(user.class)
        .take(3)
        .skip(1);

等同于

select a.* from user as a limit 3 offset 1

---

9.toList

返回List结果集

默认为ArrayList

List<User> res = baseDao.query(User.class).toList();
//单表情况下可以在无select的情况下直接toList，此时会返回查询的pojo类的集合

List<User> res = baseDao.query(User.class).select(a->a).toList();
//select a.* from user as a

List<Integer> res = baseDao.query(User.class).select(a->a.getId).toList();
//select a.id from user as a

List<MyType> res = baseDao.query(User.class)
                            .where(a -> a.getId == 5)
                            .select(a -> (MyType) new MyType(){{
                                    setId(a.getId);
                                    setName(a.getName);
                            }})
                            .toList();
//select a.id,a.name from user as a where a.id = 5

---

10.toMap

返回Map结果集

默认为HashMap

Map<Integer,User> res = baseDao.query(User.class).toMap(k -> k.getId()); //参数为一个表达式时，对返回的集合进行遍历获取MapKey
//select a.* from user as a

Map<Integer,String> res = baseDao.query(User.class).toMap(k -> k.getId(),v -> v.getName()); //参数为两个个表达式时，对返回的集合进行遍历同时获取MapKey和MapValue
//select a.* from user as a

新增(save)

1.save(obj)

对一个pojo对象的除@Id注解字段外的非null字段插入数据库

2.save(objList)

pojo对象列表的批量插入，条件同上

更新(update)

todo

删除(delete)

todo