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feat(linear_algebra/matrix):
M
maps some v ≠ 0
to zero iff `det M…
… = 0` (#9041) A result I have wanted for a long time: the two notions of a "singular" matrix are equivalent over an integral domain. Namely, a matrix `M` is singular iff it maps some nonzero vector to zero, which happens iff its determinant is zero. Here, I find such a `v` by going through the field of fractions, where everything is a lot easier because all injective endomorphisms are automorphisms. Maybe a bit overkill (and unsatisfying constructively), but it works and is a lot nicer to write out than explicitly finding an element of the kernel.
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