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[Merged by Bors] - feat(LinearAlgebra/PiTensorProduct): arbitrary tensor product of algebras #9395
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Co-authored-by: Eric Wieser <wieser.eric@gmail.com>
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…bras (#9395) Let $R$ be a commutative ring and $(A_i)$ a bunch of $R$-algebras, then $\bigotimes_{R} A$ is an $R$-algebra as well. In particular, taking $R$ to be $\mathbb{Z}$, we get tensor product of rings Co-authored-by: Riccardo Brasca <riccardo.brasca@gmail.com> Co-authored-by: Eric Wieser <wieser.eric@gmail.com>
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feat(LinearAlgebra/PiTensorProduct): arbitrary tensor product of algebras
[Merged by Bors] - feat(LinearAlgebra/PiTensorProduct): arbitrary tensor product of algebras
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…bras (#9395) Let $R$ be a commutative ring and $(A_i)$ a bunch of $R$-algebras, then $\bigotimes_{R} A$ is an $R$-algebra as well. In particular, taking $R$ to be $\mathbb{Z}$, we get tensor product of rings Co-authored-by: Riccardo Brasca <riccardo.brasca@gmail.com> Co-authored-by: Eric Wieser <wieser.eric@gmail.com>
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…bras (#9395) Let $R$ be a commutative ring and $(A_i)$ a bunch of $R$-algebras, then $\bigotimes_{R} A$ is an $R$-algebra as well. In particular, taking $R$ to be $\mathbb{Z}$, we get tensor product of rings Co-authored-by: Riccardo Brasca <riccardo.brasca@gmail.com> Co-authored-by: Eric Wieser <wieser.eric@gmail.com>
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…bras (#9395) Let $R$ be a commutative ring and $(A_i)$ a bunch of $R$-algebras, then $\bigotimes_{R} A$ is an $R$-algebra as well. In particular, taking $R$ to be $\mathbb{Z}$, we get tensor product of rings Co-authored-by: Riccardo Brasca <riccardo.brasca@gmail.com> Co-authored-by: Eric Wieser <wieser.eric@gmail.com>
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…bras (#9395) Let $R$ be a commutative ring and $(A_i)$ a bunch of $R$-algebras, then $\bigotimes_{R} A$ is an $R$-algebra as well. In particular, taking $R$ to be $\mathbb{Z}$, we get tensor product of rings Co-authored-by: Riccardo Brasca <riccardo.brasca@gmail.com> Co-authored-by: Eric Wieser <wieser.eric@gmail.com>
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Let$R$ be a commutative ring and $(A_i)$ a bunch of $R$ -algebras, then $\bigotimes_{R} A$ is an $R$ -algebra as well. In particular, taking $R$ to be $\mathbb{Z}$ , we get tensor product of rings
TensorProduct.map₂
#10986 (so that the doc string can refer to binary tensor product)