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esp32/machine_pwm: Implement duty_u16() and duty_ns() PWM methods.
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The methods duty_u16() and duty_ns() are implemented to match the existing
docs.  The duty will remain the same when the frequency is changed.
Standard ESP32 as well as S2, S3 and C3 are supported.

Thanks to @kdschlosser for the fix for rounding in resolution calculation.

Documentation is updated and examples expanded for esp32, including the
quickref and tutorial.  Additional notes are added to the machine.PWM docs
regarding limitations of hardware PWM.
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IhorNehrutsa authored and dpgeorge committed Dec 3, 2021
1 parent a7fa18c commit b491967
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22 changes: 14 additions & 8 deletions docs/esp32/quickref.rst
Expand Up @@ -218,20 +218,24 @@ range from 1Hz to 40MHz but there is a tradeoff; as the base frequency
*increases* the duty resolution *decreases*. See
`LED Control <https://docs.espressif.com/projects/esp-idf/en/latest/api-reference/peripherals/ledc.html>`_
for more details.
Currently the duty cycle has to be in the range of 0-1023.

Use the ``machine.PWM`` class::
Use the :ref:`machine.PWM <machine.PWM>` class::

from machine import Pin, PWM

pwm0 = PWM(Pin(0)) # create PWM object from a pin
pwm0.freq() # get current frequency (default 5kHz)
pwm0.freq(1000) # set frequency
pwm0.duty() # get current duty cycle (default 512, 50%)
pwm0.duty(200) # set duty cycle
pwm0.deinit() # turn off PWM on the pin
pwm0 = PWM(Pin(0)) # create PWM object from a pin
pwm0.freq() # get current frequency (default 5kHz)
pwm0.freq(1000) # set PWM frequency from 1Hz to 40MHz
pwm0.duty() # get current duty cycle, range 0-1023 (default 512, 50%)
pwm0.duty(256) # set duty cycle from 0 to 1023 as a ratio duty/1023, (now 25%)
pwm0.duty_u16(2**16*3//4) # set duty cycle from 0 to 65535 as a ratio duty_u16/65535, (now 75%)
pwm0.duty_u16() # get current duty cycle, range 0-65535
pwm0.duty_ns(250_000) # set pulse width in nanoseconds from 0 to 1_000_000_000/freq, (now 25%)
pwm0.duty_ns() # get current pulse width in ns
pwm0.deinit() # turn off PWM on the pin

pwm2 = PWM(Pin(2), freq=20000, duty=512) # create and configure in one go
print(pwm2) # view PWM settings

ESP chips have different hardware peripherals:

Expand All @@ -251,6 +255,8 @@ but only 8 different PWM frequencies are available, the remaining 8 channels mus
have the same frequency. On the other hand, 16 independent PWM duty cycles are
possible at the same frequency.

See more examples in the :ref:`esp32_pwm` tutorial.

ADC (analog to digital conversion)
----------------------------------

Expand Down
106 changes: 86 additions & 20 deletions docs/esp32/tutorial/pwm.rst
@@ -1,4 +1,4 @@
.. _esp32_pwm:
.. _esp32_pwm:

Pulse Width Modulation
======================
Expand All @@ -11,7 +11,7 @@ compared with the length of a single period (low plus high time). Maximum
duty cycle is when the pin is high all of the time, and minimum is when it is
low all of the time.

More comprehensive example with all 16 PWM channels and 8 timers::
* More comprehensive example with all 16 PWM channels and 8 timers::

from machine import Pin, PWM
try:
Expand All @@ -29,21 +29,87 @@ More comprehensive example with all 16 PWM channels and 8 timers::
except:
pass

Output is::

PWM(pin=15, freq=100, duty=64, resolution=10, mode=0, channel=0, timer=0)
PWM(pin=2, freq=100, duty=128, resolution=10, mode=0, channel=1, timer=0)
PWM(pin=4, freq=200, duty=192, resolution=10, mode=0, channel=2, timer=1)
PWM(pin=16, freq=200, duty=256, resolution=10, mode=0, channel=3, timer=1)
PWM(pin=18, freq=300, duty=320, resolution=10, mode=0, channel=4, timer=2)
PWM(pin=19, freq=300, duty=384, resolution=10, mode=0, channel=5, timer=2)
PWM(pin=22, freq=400, duty=448, resolution=10, mode=0, channel=6, timer=3)
PWM(pin=23, freq=400, duty=512, resolution=10, mode=0, channel=7, timer=3)
PWM(pin=25, freq=500, duty=576, resolution=10, mode=1, channel=0, timer=0)
PWM(pin=26, freq=500, duty=640, resolution=10, mode=1, channel=1, timer=0)
PWM(pin=27, freq=600, duty=704, resolution=10, mode=1, channel=2, timer=1)
PWM(pin=14, freq=600, duty=768, resolution=10, mode=1, channel=3, timer=1)
PWM(pin=12, freq=700, duty=832, resolution=10, mode=1, channel=4, timer=2)
PWM(pin=13, freq=700, duty=896, resolution=10, mode=1, channel=5, timer=2)
PWM(pin=32, freq=800, duty=960, resolution=10, mode=1, channel=6, timer=3)
PWM(pin=33, freq=800, duty=1023, resolution=10, mode=1, channel=7, timer=3)
Output is::

PWM(Pin(15), freq=100, duty=64, resolution=10, mode=0, channel=0, timer=0)
PWM(Pin(2), freq=100, duty=128, resolution=10, mode=0, channel=1, timer=0)
PWM(Pin(4), freq=200, duty=192, resolution=10, mode=0, channel=2, timer=1)
PWM(Pin(16), freq=200, duty=256, resolution=10, mode=0, channel=3, timer=1)
PWM(Pin(18), freq=300, duty=320, resolution=10, mode=0, channel=4, timer=2)
PWM(Pin(19), freq=300, duty=384, resolution=10, mode=0, channel=5, timer=2)
PWM(Pin(22), freq=400, duty=448, resolution=10, mode=0, channel=6, timer=3)
PWM(Pin(23), freq=400, duty=512, resolution=10, mode=0, channel=7, timer=3)
PWM(Pin(25), freq=500, duty=576, resolution=10, mode=1, channel=0, timer=0)
PWM(Pin(26), freq=500, duty=640, resolution=10, mode=1, channel=1, timer=0)
PWM(Pin(27), freq=600, duty=704, resolution=10, mode=1, channel=2, timer=1)
PWM(Pin(14), freq=600, duty=768, resolution=10, mode=1, channel=3, timer=1)
PWM(Pin(12), freq=700, duty=832, resolution=10, mode=1, channel=4, timer=2)
PWM(Pin(13), freq=700, duty=896, resolution=10, mode=1, channel=5, timer=2)
PWM(Pin(32), freq=800, duty=960, resolution=10, mode=1, channel=6, timer=3)
PWM(Pin(33), freq=800, duty=1023, resolution=10, mode=1, channel=7, timer=3)

* Example of a smooth frequency change::

from utime import sleep
from machine import Pin, PWM

F_MIN = 500
F_MAX = 1000

f = F_MIN
delta_f = 1

p = PWM(Pin(5), f)
print(p)

while True:
p.freq(f)

sleep(10 / F_MIN)

f += delta_f
if f >= F_MAX or f <= F_MIN:
delta_f = -delta_f

See PWM wave at Pin(5) with an oscilloscope.

* Example of a smooth duty change::

from utime import sleep
from machine import Pin, PWM

DUTY_MAX = 2**16 - 1

duty_u16 = 0
delta_d = 16

p = PWM(Pin(5), 1000, duty_u16=duty_u16)
print(p)

while True:
p.duty_u16(duty_u16)

sleep(1 / 1000)

duty_u16 += delta_d
if duty_u16 >= DUTY_MAX:
duty_u16 = DUTY_MAX
delta_d = -delta_d
elif duty_u16 <= 0:
duty_u16 = 0
delta_d = -delta_d

See PWM wave at Pin(5) with an oscilloscope.

Note: the Pin.OUT mode does not need to be specified. The channel is initialized
to PWM mode internally once for each Pin that is passed to the PWM constructor.

The following code is wrong::

pwm = PWM(Pin(5, Pin.OUT), freq=1000, duty=512) # Pin(5) in PWM mode here
pwm = PWM(Pin(5, Pin.OUT), freq=500, duty=256) # Pin(5) in OUT mode here, PWM is off

Use this code instead::

pwm = PWM(Pin(5), freq=1000, duty=512)
pwm.init(freq=500, duty=256)
31 changes: 31 additions & 0 deletions docs/library/machine.PWM.rst
Expand Up @@ -77,3 +77,34 @@ Methods
With no arguments the pulse width in nanoseconds is returned.

With a single *value* argument the pulse width is set to that value.

Limitations of PWM
------------------

* Not all frequencies can be generated with absolute accuracy due to
the discrete nature of the computing hardware. Typically the PWM frequency
is obtained by dividing some integer base frequency by an integer divider.
For example, if the base frequency is 80MHz and the required PWM frequency is
300kHz the divider must be a non-integer number 80000000 / 300000 = 266.67.
After rounding the divider is set to 267 and the PWM frequency will be
80000000 / 267 = 299625.5 Hz, not 300kHz. If the divider is set to 266 then
the PWM frequency will be 80000000 / 266 = 300751.9 Hz, but again not 300kHz.

* The duty cycle has the same discrete nature and its absolute accuracy is not
achievable. On most hardware platforms the duty will be applied at the next
frequency period. Therefore, you should wait more than "1/frequency" before
measuring the duty.

* The frequency and the duty cycle resolution are usually interdependent.
The higher the PWM frequency the lower the duty resolution which is available,
and vice versa. For example, a 300kHz PWM frequency can have a duty cycle
resolution of 8 bit, not 16-bit as may be expected. In this case, the lowest
8 bits of *duty_u16* are insignificant. So::

pwm=PWM(Pin(13), freq=300_000, duty_u16=2**16//2)

and::

pwm=PWM(Pin(13), freq=300_000, duty_u16=2**16//2 + 255)

will generate PWM with the same 50% duty cycle.

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