BSON::ObjectId#inspect returns a string that evals into an object id

[tonyta]

This will let BSON::ObjectId#inspect to return a string that can be evaluated into an equivalent object id. This would be super useful for copying and pasting object ids (especially when used with Mongoid).

A BSON.ObjectId constructor method passes the argument to #from_string, allowing object ids to behave kinda like literals.

Seemingly sending an arg to a constant as a constructor is similar to some behavior found in the standard lib: Pathname('./lib') or Hash(a: 1, b: 2)

If this is helpful, perhaps something similar can be implemented for BSON::Binary as well.

Now

>> BSON::ObjectId.new
=> BSON::ObjectId('559afa3e546f6e2631000000')

>> BSON::ObjectId('559afa3e546f6e2631000000')
=> BSON::ObjectId('559afa3e546f6e2631000000')
😃😃😃😃

# Mongoid
>> Song.first.attributes
=> {"_id"=>BSON::ObjectId('559b0037546f6e28440a0000'),
   "length"=>219,
   "name"=>"Shake It Off",
   "artist_id"=>BSON::ObjectId('559afff3546f6e2844030000'),
   "album_id"=>BSON::ObjectId('559aff93546f6e2844020000')}

>> {"_id"=>BSON::ObjectId('559b0037546f6e28440a0000'), "length"=>219, "name"=>"Shake It Off", "artist_id"=>BSON::ObjectId('559afff3546f6e2844030000'), "album_id"=>BSON::ObjectId('559aff93546f6e2844020000')}
=> {"_id"=>BSON::ObjectId('559b0037546f6e28440a0000'),
   "length"=>219,
   "name"=>"Shake It Off",
   "artist_id"=>BSON::ObjectId('559afff3546f6e2844030000'),
   "album_id"=>BSON::ObjectId('559aff93546f6e2844020000')}

Before (990c7157)

>> BSON::ObjectId.new
=> <BSON::ObjectId:0x70280035828000 data=559afa3e546f6e2631000000>

>> <BSON::ObjectId:0x70280035828000 data=559afa3e546f6e2631000000>
😡 SyntaxError: unexpected '<', expecting end-of-input

Way Before (27d9a915)

>> BSON::ObjectId.new
=> BSON::ObjectId('559afa3e546f6e2631000000')

>> BSON::ObjectId('559afa3e546f6e2631000000')
😡 NoMethodError: undefined method `ObjectId' for BSON:Module

Hope this helps!

[estolfo]

Cool, thanks!

[jonhyman]

@tonyta thanks, I'm upgrading our code base to the new driver and was going to submit something similar, so glad you did this!

[tonyta]

@jonhyman Thank you for all your awesome work! I'm happy to have helped! 😸