Render element regardless of its position on the page

[OneGeek]

Added options.renderRootAtOrigin flag, when set to true the element being rendered will be rendered at 0,0 instead of at its actual page position. However, as it is now the resulting image will be the full page's dimensions instead of the target element's.

Haven't yet figured out exactly where the final image size is determined, so the resulting image needs to be cropped. Not sure what will happen if the element to be rendered is taller than whatever size is currently chosen for the image.

[OneGeek]

Darn, screwed something up, working on fixing it.

[OneGeek]

Nevermind, it works fine, I had stopped including jquery by mistake

[niklasvh]

Thanks for the pull request. However, I am bit confused as to how this is different from using a specific element to render as in 0cb252a / http://html2canvas.hertzen.com/tests/origin.html ?

[OneGeek]

Hmm, when I tried to render a single element only as much as was visible on
the page itself would be rendered, and that would get stretched to the size
of the whole widget, I'll look into this more to see if I was doing it
wrong.

On Thu, Apr 12, 2012 at 3:59 PM, Niklas von Hertzen <
reply@reply.github.com

wrote:

Thanks for the pull request. However, I am bit confused as to how this is
different from using a specific element to render as in
https://github.com/niklasvh/html2canvas/commit/0cb252ada91c84ef411288b317c03e97da1f12ad/
http://html2canvas.hertzen.com/tests/origin.html ?

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