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modified: advancedantennaProblemSet3Problem1.tex
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deleted:    dualFarField.tex
modified:   ../ece1229/chapter4Notes.tex
new file:   ../ece1229/chapter4NotesPart2.tex
new file:   ../ece1229/dualFarField.tex
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peeterjoot committed Feb 28, 2015
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6 changes: 4 additions & 2 deletions bin/latexRegex.pl
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#s/\\up\b/\\uparrow/g ;
#s/\\Veff/V_{\\mathrm{eff}}/g ;
#s/\\Veph/V_{\\mathrm{e,ph}}/g ;
#s/\^a/^{(a)}/g;
#s/\^b/^{(b)}/g;
#s/\^classical/^{\\mathrm{classical}}/g ;
#s/\bialpha\b/{i_\\alpha}/g ;
#s/\tY\b/\\tilde{Y}/g ;
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#s/pidotalpha/\\dot{p}_{i_\\alpha}/g ;
#s/xialpha\b/x_{i_\\alpha}/g ;
#s/xidotalpha/\\dot{x}_{i_\\alpha}/g ;
s/\^a/^{(a)}/g;
s/\^b/^{(b)}/g;
s/_eo/_{\\textrm{eo}}/g ;
s/_mo/_{\\textrm{mo}}/g ;
2 changes: 1 addition & 1 deletion env/.aspell.en.prepl
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divding dividing
coloumb's Coulomb's
gausses Gauss's
cooresponds corresponds
waave wave
cooresponds corresponds
diagonize diagonalize
convience convenience
refections reflections
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24 changes: 12 additions & 12 deletions env/.aspell.en.pws
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relativistic
integrands
extremum
Ficks
Fick's
Ficks
pseudoinverse
unstretched
orthonormalization
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imaginaries
n'l'm
nlm
PDE
Lut
PDE
quantized
Guoy
Minkowski
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dk
dL
dm
dn
dN
dp
dn
dP
dp
Debye
dQ
dq
dQ
Doran
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kx
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nl
nm
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129 changes: 125 additions & 4 deletions notes/blogit/advancedantennaProblemSet3Problem1.tex
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% Licenced as described in the file LICENSE under the root directory of this GIT repository.
%
\makeproblem{Superposition of electric and magnetic dipoles}{advancedantenna:problemSet3:1}{

An infinitesimal electric dipole of electric current strength \( I_{\textrm{eo}} \) is oriented along the x-axis. With this there is also an infinitesimal magnetic dipole of magnetic current strength \( I_{\textrm{mo}} \) but oriented along the y-axis.

\makesubproblem{}{advancedantenna:problemSet3:1a}
Expand All @@ -20,11 +19,133 @@
\makeanswer{advancedantenna:problemSet3:1}{
\makeSubAnswer{}{advancedantenna:problemSet3:1a}

TODO.
The far field electric field induced by the electric current can be calculated with the transverse projection

\begin{dmath}\label{eqn:advancedantennaProblemSet3Problem1:20}
\BE_\txte
= - j \omega \Proj_\T \BA
= - j \omega \lr{ \BA - (\BA \cdot \kcap) \kcap },
\end{dmath}

where

\begin{dmath}\label{eqn:advancedantennaProblemSet3Problem1:40}
\BA = \xcap \frac{\mu_0 I_{\textrm{eo}} l}{4 \pi r} e^{-j k r}.
\end{dmath}

To simplify this, note that the Cartesian to spherical coordinates mapping is

\begin{subequations}
\label{eqn:advancedantennaProblemSet3Problem1:60}
\begin{dmath}\label{eqn:advancedantennaProblemSet3Problem1:80}
\xcap = \sin\theta \cos\phi \kcap + \cos\theta \cos\phi \thetacap - \sin\phi \phicap
\end{dmath}
\begin{dmath}\label{eqn:advancedantennaProblemSet3Problem1:100}
\ycap = \sin\theta \sin\phi \kcap + \cos\theta \sin\phi \thetacap + \cos\phi \phicap
\end{dmath}
\begin{dmath}\label{eqn:advancedantennaProblemSet3Problem1:120}
\zcap = \cos\theta \kcap - \sin\theta \thetacap,
\end{dmath}
\end{subequations}

so

\begin{dmath}\label{eqn:advancedantennaProblemSet3Problem1:140}
\BE_\txte
= - j \omega
\lr{ \cos\theta \cos\phi \thetacap - \sin\phi \phicap }
\frac{\mu_0 I_{\textrm{eo}} l}{4 \pi r} e^{-j k r}.
\end{dmath}

For the magnetic current, first note that the far field magnetic field for an electric current can also be expressed in terms of the magnetic vector potential

\begin{dmath}\label{eqn:advancedantennaProblemSet3Problem1:160}
\BH
= \inv{\eta} \kcap \cross \BE
= -j\frac{\omega}{\eta} \kcap \cross \lr{ \BA - (\BA \cdot \kcap)\kcap }
= -j\frac{\omega}{\eta} \kcap \cross \BA.
\end{dmath}

Duality provides the far field electric field given an electric vector potential

\begin{dmath}\label{eqn:advancedantennaProblemSet3Problem1:180}
\BE_\txtm = j \omega \eta \kcap \cross \BF.
\end{dmath}

For the y-axis oriented magnetic current, the vector potential is

\begin{dmath}\label{eqn:advancedantennaProblemSet3Problem1:200}
\BF = \ycap \frac{\epsilon_0 I_{\textrm{mo}} l}{4 \pi r} e^{-j k r}.
\end{dmath}

The electric field will be directed along

\begin{dmath}\label{eqn:advancedantennaProblemSet3Problem1:220}
\kcap \cross \ycap
=
\kcap \cross
\lr{
\sin\theta \sin\phi \kcap + \cos\theta \sin\phi \thetacap + \cos\phi \phicap
}
=
\cos\theta \sin\phi \phicap - \cos\phi \thetacap,
\end{dmath}

so

\begin{dmath}\label{eqn:advancedantennaProblemSet3Problem1:240}
\BE_\txtm
= j \omega \eta
\lr{
\cos\theta \sin\phi \phicap - \cos\phi \thetacap
}
\frac{\epsilon_0 I_{\textrm{mo}} l}{4 \pi r} e^{-j k r}.
\end{dmath}

Summing \cref{eqn:advancedantennaProblemSet3Problem1:140}, and \cref{eqn:advancedantennaProblemSet3Problem1:240} gives

%\begin{dmath}\label{eqn:advancedantennaProblemSet3Problem1:260}
\boxedEquation{eqn:advancedantennaProblemSet3Problem1:260}{
\BE
=
j \omega
\frac{l}{4 \pi r} e^{-j k r} \eta \epsilon_0
\lr{
\lr{ -\cos\theta \cos\phi \thetacap + \sin\phi \phicap } \eta I_{\textrm{eo}}
+
\lr{ \cos\theta \sin\phi \phicap - \cos\phi \thetacap } I_{\textrm{mo}}
}
}
%\end{dmath}

\makeSubAnswer{}{advancedantenna:problemSet3:1b}

TODO.
When \( \eta I_{\textrm{eo}} = I_{\textrm{mo}} \), this reduces to

\begin{dmath}\label{eqn:advancedantennaProblemSet3Problem1:280}
\BE
=
j \omega
\frac{\mu_0 I_{\textrm{eo}} l}{4 \pi r} e^{-j k r}
\lr{ 1 + \cos\theta }
\lr{
-\cos\phi \thetacap
+ \sin\phi \phicap
}.
\end{dmath}

\makeSubAnswer{}{advancedantenna:problemSet3:1c}

TODO.
In the zy plane, \( \phi = \pi/2 \), and the electric field has only a \( \phicap \) component

\begin{dmath}\label{eqn:advancedantennaProblemSet3Problem1:n}
\BE
=
j \omega
\frac{\mu_0 I_{\textrm{eo}} l}{4 \pi r} e^{-j k r}
\lr{ 1 + \cos\theta }
\phicap
\end{dmath}

PLOT: TODO.
}
67 changes: 0 additions & 67 deletions notes/blogit/dualFarField.tex

This file was deleted.

13 changes: 3 additions & 10 deletions notes/blogit/renumber
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#~/bin/lgrep numberGame.tex | tee o ; . ./o
#~/bin/lgrep pathria72typoPossibility.tex | tee o ; . ./o
#~/bin/lgrep pipeFlowConstPressureGradient.tex | tee o ; . ./o
~/bin/lgrep t.tex | tee o ; . ./o
#~/bin/lgrep t.tex | tee o ; . ./o
#perl -p -i ./p ../blogit/bitcoin.tex
#perl -p -i ./p ../blogit/mortgageInterest.tex
#perl -p -i ./p ../blogit/numberGame.tex
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#~/bin/lgrep advancedantennaProblemSet3.tex | tee o ; . ./o
#perl -p -i ./p ../blogit/advancedantennaProblemSet3.tex

#~/bin/lgrep advancedantennaProblemSet3Problem1.tex | tee o ; . ./o
~/bin/lgrep advancedantennaProblemSet3Problem1.tex | tee o ; . ./o
#~/bin/lgrep advancedantennaProblemSet3Problem2.tex | tee o ; . ./o
#~/bin/lgrep advancedantennaProblemSet3Problem3.tex | tee o ; . ./o
#~/bin/lgrep advancedantennaProblemSet3Problem4.tex | tee o ; . ./o
#~/bin/lgrep advancedantennaProblemSet3Problem5.tex | tee o ; . ./o
#perl -p -i ./p ../blogit/advancedantennaProblemSet3Problem1.tex
perl -p -i ./p ../blogit/advancedantennaProblemSet3Problem1.tex
#perl -p -i ./p ../blogit/advancedantennaProblemSet3Problem2.tex
#perl -p -i ./p ../blogit/advancedantennaProblemSet3Problem3.tex
#perl -p -i ./p ../blogit/advancedantennaProblemSet3Problem4.tex
#perl -p -i ./p ../blogit/advancedantennaProblemSet3Problem5.tex

#~/bin/lgrep chapter5Notes.tex | tee o ; . ./o
#perl -p -i ./p ../blogit/chapter5Notes.tex

#~/bin/lgrep reciprocityTheorem.tex | tee o ; . ./o
#perl -p -i ./p ../blogit/reciprocityTheorem.tex


~/bin/lgrep dualFarField.tex | tee o ; . ./o
#perl -p -i ./p ../blogit/dualFarField.tex
2 changes: 2 additions & 0 deletions notes/blogit/tex2mathjax
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Expand Up @@ -117,7 +117,9 @@ foreach (@$rLines)
s/\\textAndIndex{(.*?)}/$1/g ;
s/\\implies/\\Rightarrow/g ;
s/\\chaptext/ch./g ;
s/\\tabtext/tab./g ;
s/\\S/section/g ;
s/\\Proj\b/\\textrm{Proj}/g ;

s/^ *%.*// ;
s/^ *\\input.*// ;
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8 changes: 8 additions & 0 deletions notes/ece1229/METADATA
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Expand Up @@ -106,6 +106,14 @@ my @ece1229 =
URL => 'http://peeterjoot.com/archives/math2015/gaMagneticSourcesToTensorToVector.pdf',
WHAT => qq()
}
,{
SOURCE => 'dualFarField',
TITLE => qq(Duality transformation of the far field fields.),
DATE => 'February 27, 2015',
REF => 'dualFarField',
URL => 'http://peeterjoot.com/archives/math2015/dualFarField.pdf',
WHAT => qq()
}
) ; # @ece1229
return @ece1229 ;
}
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