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Count combinations with replacement #737
Count combinations with replacement #737
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I believe you that this is correct, but I have a hard time comprehending this without comments. Is it the "stars and sticks" thing that leads to
binomial(n+k-1, k)
?Could you comment the loop similar to what we did in the other cases?
In addition: Could
n+k
overflow? And if so, shouldn't we returnNone
here instead ofpanic
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I chose the expression "stars and bars" from wikipedia, expression I did not know. I added a comment.
Good catch
n+k
overflowing, handled.And I copied/updated the previous comment about the loop.