New issue
Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.
By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.
Already on GitHub? Sign in to your account
Implement %%fortran in Jupyter #22654
Comments
Commit: |
Author: Jeroen Demeyer |
New commits:
|
Reviewer: Volker Braun |
comment:4
|
Branch pushed to git repo; I updated commit sha1. This was a forced push. New commits:
|
comment:7
Code works. It took me a while to understand how to use that FIB function:
in a cell returns Finally, the doc from
|
Changed keywords from none to days86 |
Branch pushed to git repo; I updated commit sha1. This was a forced push. New commits:
|
comment:10
Thanks! I added the doctest (and rebased on 8.0.beta2). |
Changed reviewer from Volker Braun to Volker Braun, Sébastien Labbé |
Changed branch from u/jdemeyer/implement___fortran_in_jupyter to |
CC: @kcrisman
Component: notebook
Keywords: days86
Author: Jeroen Demeyer
Branch/Commit:
6cf97b0
Reviewer: Volker Braun, Sébastien Labbé
Issue created by migration from https://trac.sagemath.org/ticket/22654
The text was updated successfully, but these errors were encountered: