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minor #4755 fix minor typo (xabbuh)

This PR was merged into the 2.3 branch.

Discussion
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fix minor typo

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5dca2e1 fix minor typo
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wouterj committed Jan 8, 2015
2 parents 463c30b + 5dca2e1 commit 4e880c1dba02924ccfef47049c2dd4dc14f2db65
Showing with 9 additions and 8 deletions.
  1. +9 −8 book/security.rst
@@ -204,7 +204,7 @@ user to be logged in to access this URL:
# ...
firewalls:
# ...
access_control:
# require ROLE_ADMIN for /admin*
- { path: ^/admin, roles: ROLE_ADMIN }
@@ -427,9 +427,10 @@ If you'd like to load your users via the Doctrine ORM, that's easy! See
:doc:`/cookbook/security/entity_provider` for all the details.
.. _book-security-encoding-user-password:
.. _c-encoding-the-users-password:
C) Encoding the Users Password
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
C) Encoding the User's Password
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Whether your users are stored in ``security.yml``, in a database or somewhere
else, you'll want to encode their passwords. The best algorithm to use is
@@ -668,7 +669,7 @@ URL pattern. You saw this earlier, where anything matching the regular expressio
# ...
firewalls:
# ...
access_control:
# require ROLE_ADMIN for /admin*
- { path: ^/admin, roles: ROLE_ADMIN }
@@ -834,9 +835,9 @@ in this chapter).
Be careful with this in your layout or on your error pages! Because of
some internal Symfony details, to avoid broken error pages in the ``prod``
environment, wrap calls in these templates with a check for ``app.user``:
.. code-block:: html+jinja
{% if app.user and is_granted('ROLE_ADMIN') %}
Securing other Services
@@ -970,7 +971,7 @@ the User object, and use the ``isGranted`` method (or
// boo :(. Never check for the User object to see if they're logged in
if ($this->getUser()) {
}
Retrieving the User in a Template
@@ -989,7 +990,7 @@ key:
.. code-block:: html+php
<?php if ($view['security']->isGranted('IS_AUTHENTICATED_FULLY')): ?>
<?php if ($view['security']->isGranted('IS_AUTHENTICATED_FULLY')): ?>
<p>Username: <?php echo $app->getUser()->getUsername() ?></p>
<?php endif; ?>

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