rank calculated incorrectly

[nbeloglazov]

Example:

(rank (matrix [[1 2 3] [1 2 3]])) 

Real rank is 1 (rows are linearly dependant). Function returns 2.
I think the problem with svd function. It's documentation says:

(svd A) computes the sparse singular value decomposition of A
  returning a map with keys {:values L :left U :right V} such that
  A = U (diag L) V. If (size A) is [n m] and the rank of A is
  k, we have the size of U as [n k], (diag L) as [k k],
  and (t V) as [k m].

But it's not true. In jblas size of L calculated as min(n, m), not as rank of a matrix. Check this: https://github.com/mikiobraun/jblas/blob/master/src/main/java/org/jblas/Singular.java#L26

I think correct solution is to calculate number of non zero elements of L.

Thanks to Kevin for bug: https://groups.google.com/forum/#!topic/incanter/eINeIuV2Ktw