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Send output of maintenance/update.php to stdout #348

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AndrewKostka
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array_push( $out, $line );
}

while( $line = fgets( $stderrProc ) ) {
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It's a little unclear to me if this means that we end up batching up all the internal stdout lines and output each of those to the main stdout (and also store in $out) before only then addressing the stderr batch.

e.g. if we have a command that runs for an hour and the first thing to happen is something on STDERR would we see nothing at all until STDOUT has got to the end of the stream. I suspect we might find this a little misleading if it's the case.

My attempts to test this but putting something like:

                $stdout = fopen( 'php://stderr', 'w');
		fwrite( $stdout, “hello, world\n”);
		fclose($stdout);

in update.php simply resulted in having no output of at all from the inner script

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@deer-wmde deer-wmde Apr 20, 2023

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I sadly only can confirm your assumption. I tried to find a way around it but not successfully. For example, I wrapped the two while() loops in a while(proc_get_status( $proc ) )[ 'running' ]) and turned the while($line = fgets( ... into if statements. And while that alternates between writing stdout and stderr output, it doesn't make sure that you get everything in the right order and (even worse) that you get every line at all.

$mwPath = realpath( __DIR__ . '/../../../' );
$cmd = 'WBS_DOMAIN=' . $GLOBALS[WBSTACK_INFO_GLOBAL]->requestDomain . ' php ' . $mwPath . '/maintenance/update.php --quick';
exec($cmd, $out, $return);
$cmd = 'WBS_DOMAIN=' . $domain . ' php ' . $mwPath . '/maintenance/update.php --quick';
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I think it might be worth trying if we can have the command itself redirect stderr to stdout like this:

$cmd = 'WBS_DOMAIN=' . $domain . ' php ' . $mwPath . '/maintenance/update.php --quick 2>&1';

which in case it does work could save us a few hoops to jump through in here.

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4 participants