用python写的全民漂移游戏脚本
- 在抽奖页面点击+5,会开始播放15秒广告;
- 广告播放完毕,需要点击关闭广告才能回抽奖页面,并增加抽奖次数5次;
- 点击开始,转盘会转5~7秒,然后页面显示抽奖结果;
- 抽奖结果会有两种情况,一是可以直接点击领取的,二是需要再次观看广告再领取的,也可以点击关闭重新抽奖;
- 抽奖次数不够自动播放广告增加抽奖次数;
- 自动点击抽奖,并领取奖励;
- 遇到要观看广告才能领取的奖励,点击关掉,重新抽(这里主要是为了省时)
用到的库:
import os
from PIL import Image
from PIL import ImageFile
import imagehash
import threading
import time
其中,641 61 是点击位置的xy坐标。怎么查看点击位置坐标可以参考我的这篇博客: https://blog.csdn.net/qq_23521659/article/details/95475787
首先截图上传:
os.system('adb shell screencap -p /sdcard/nowPage.png')
os.system('adb pull /sdcard/nowPage.png .')
然后裁切:
img = Image.open("nowPage.png")
cropped = img.crop((300, 690, 420, 810)) # (left, upper, right, lower)
cropped.save("nowButton.png")
识别函数如下:
def get_hash_dict(dir):
hash_dict = {}
image_quantity = 0
for _, _, files in os.walk(dir):
for i, fileName in enumerate(files):
with open(dir + fileName, 'rb') as fp:
hash_dict[dir + fileName] = imagehash.average_hash(Image.open(fp))
image_quantity += 1
return hash_dict, image_quantity
def compare_image_with_hash(image_file_name_1, image_file_name_2, max_dif=0):
ImageFile.LOAD_TRUNCATED_IMAGES = True
hash_1 = None
hash_2 = None
with open(image_file_name_1, 'rb') as fp:
hash_1 = imagehash.average_hash(Image.open(fp))
with open(image_file_name_2, 'rb') as fp:
hash_2 = imagehash.average_hash(Image.open(fp))
dif = hash_1 - hash_2
if dif < 0:
dif = -dif
if dif <= max_dif:
return True
else:
return False
def compare_image_dir_with_hash(dir_1, dir_2, max_dif=0):
ImageFile.LOAD_TRUNCATED_IMAGES = True
hash_dict_1, image_quantity_1 = get_hash_dict(dir_1)
hash_dict_2, image_quantity_2 = get_hash_dict(dir_2)
if image_quantity_1 > image_quantity_2:
tmp = image_quantity_1
image_quantity_1 = image_quantity_2
image_quantity_2 = tmp
tmp = hash_dict_1
hash_dict_1 = hash_dict_2
hash_dict_2 = tmp
result_dict = {}
for k in hash_dict_1.keys():
result_dict[k] = None
for dif_i in range(0, max_dif + 1):
have_none = False
for k_1 in result_dict.keys():
if result_dict.get(k_1) is None:
have_none = True
if not have_none:
return result_dict
for k_1, v_1 in hash_dict_1.items():
for k_2, v_2 in hash_dict_2.items():
sub = (v_1 - v_2)
if sub < 0:
sub = -sub
if sub == dif_i and result_dict.get(k_1) is None:
result_dict[k_1] = k_2
break
return result_dict
# 总循环函数
def run():
...
global timer
timer = threading.Timer(0.1, run)
timer.start()
# 这里进行循环
try:
timer = threading.Timer(0, run)
timer.start()
except(KeyboardInterrupt, SystemExit):
print(KeyboardInterrupt, SystemExit)