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I would like that the phone was not re-looked after a missing évent.
Personnaly I don't use password on my phone. So, I would like to see
immediately, simply by press the on/off button, if I missed something whith
your popups.
I would not have to have to unlock the phone (The notifier bar is not "sure",
i.e. if I forgot to delete old items...)
With an option "no timeout" in the keyguard, it will do this, no ?
Thank you ! Very good job !
Jackie - France
Original issue reported on code.google.com by jaclin...@gmail.com on 30 Sep 2011 at 10:30
The text was updated successfully, but these errors were encountered:
I think there is some misunderstanding of what this value does. The Wakelock &
Keyguard timeout define how long to wait after a notification is shown before
putting the phone back to sleep (the Wakelock) or locking the phone back up
(the Keyguard). If there was an option of "No Timout", that is the same as
saying " turn the screen on or don't unlock the phone". The option to not turn
the screen or or unlock the phone is located under" Settings->Screen Settings.
Let me know if you have any questions.
Original comment by cs3vi...@gmail.com on 4 Oct 2011 at 2:45
Hi.
Maybe have I not explain correctly what I would like...
I used the "advanced options" in your program to set the Wakelock and the
Wakeguard. If I set the Wakelock at 1 minute and the Wakeguard at 3 minutes,
your program do that : the popup is shown, and the screen go off after 1
min., but the phone is not looked : I press the on/off button of the phone,
and your popup is shown immediately, without the "unlock" screen. If I not
do that, and wait 3 min., then I have the unlock screen of Android.
So, if there is an option for no timeout in the Wakeguard, I think that the
phone will never looked if an event is comming. That's what I think it could
be fine. With no timeout; when I'll take the phone in my bag, after many
hours, I have just to press the on/off button to see if I have a missed
call.
This is only my impression...
Excuse me for my bad english...
And, one more time, thanks you for your great job.
Original comment by jaclin...@gmail.com on 7 Oct 2011 at 9:00
Original issue reported on code.google.com by
jaclin...@gmail.com
on 30 Sep 2011 at 10:30The text was updated successfully, but these errors were encountered: