title | sidebar_position | id |
---|---|---|
Scala Serialization Guide |
4 |
scala_guide |
Fury supports all scala object serialization:
case
class serialization supportedpojo/bean
class serialization supportedobject
singleton serialization supportedcollection
serialization supported- other types such as
tuple/either
and basic types are all supported too.
Scala 2 and 3 are both supported.
To add a dependency on Fury scala for scala 2 with sbt, use the following:
libraryDependencies += "org.apache.fury" % "fury-scala_2.13" % "0.9.0"
To add a dependency on Fury scala for scala 3 with sbt, use the following:
libraryDependencies += "org.apache.fury" % "fury-scala_3" % "0.9.0"
case class Person(name: String, id: Long, github: String)
case class Point(x : Int, y : Int, z : Int)
object ScalaExample {
val fury: Fury = Fury.builder().withScalaOptimizationEnabled(true).build()
// Register optimized fury serializers for scala
ScalaSerializers.registerSerializers(fury)
fury.register(classOf[Person])
fury.register(classOf[Point])
def main(args: Array[String]): Unit = {
val p = Person("Shawn Yang", 1, "https://github.com/chaokunyang")
println(fury.deserialize(fury.serialize(p)))
println(fury.deserialize(fury.serialize(Point(1, 2, 3))))
}
}
When using fury for scala serialization, you should create fury at least with following options:
import org.apache.fury.Fury
import org.apache.fury.serializer.scala.ScalaSerializers
val fury = Fury.builder().withScalaOptimizationEnabled(true).build()
// Register optimized fury serializers for scala
ScalaSerializers.registerSerializers(fury)
Depending on the object types you serialize, you may need to register some scala internal types:
fury.register(Class.forName("scala.Enumeration.Val"))
If you want to avoid such registration, you can disable class registration by FuryBuilder#requireClassRegistration(false)
.
Note that this option allow to deserialize objects unknown types, more flexible but may be insecure if the classes contains malicious code.
And circular references are common in scala, Reference tracking
should be enabled by FuryBuilder#withRefTracking(true)
. If you don't enable reference tracking, StackOverflowError may happen for some scala versions when serializing scala Enumeration.
Note that fury instance should be shared between multiple serialization, the creation of fury instance is not cheap.
If you use shared fury instance across multiple threads, you should create ThreadSafeFury
instead by FuryBuilder#buildThreadSafeFury()
instead.
case class Person(github: String, age: Int, id: Long)
val p = Person("https://github.com/chaokunyang", 18, 1)
println(fury.deserialize(fury.serialize(p)))
println(fury.deserializeJavaObject(fury.serializeJavaObject(p)))
class Foo(f1: Int, f2: String) {
override def toString: String = s"Foo($f1, $f2)"
}
println(fury.deserialize(fury.serialize(Foo(1, "chaokunyang"))))
object singleton {
}
val o1 = fury.deserialize(fury.serialize(singleton))
val o2 = fury.deserialize(fury.serialize(singleton))
println(o1 == o2)
val seq = Seq(1,2)
val list = List("a", "b")
val map = Map("a" -> 1, "b" -> 2)
println(fury.deserialize(fury.serialize(seq)))
println(fury.deserialize(fury.serialize(list)))
println(fury.deserialize(fury.serialize(map)))
val tuple = Tuple2(100, 10000L)
println(fury.deserialize(fury.serialize(tuple)))
val tuple = Tuple4(100, 10000L, 10000L, "str")
println(fury.deserialize(fury.serialize(tuple)))
enum Color { case Red, Green, Blue }
println(fury.deserialize(fury.serialize(Color.Green)))
object ColorEnum extends Enumeration {
type ColorEnum = Value
val Red, Green, Blue = Value
}
println(fury.deserialize(fury.serialize(ColorEnum.Green)))
val opt: Option[Long] = Some(100)
println(fury.deserialize(fury.serialize(opt)))
val opt1: Option[Long] = None
println(fury.deserialize(fury.serialize(opt1)))