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feat(smithy-client): support strict union parsing #2746
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Codecov Report
@@ Coverage Diff @@
## main #2746 +/- ##
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Coverage ? 61.41%
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Files ? 539
Lines ? 27525
Branches ? 6722
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Hits ? 16905
Misses ? 10620
Partials ? 0 Continue to review full report at Codecov.
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const setKeys = new Set<string>(); | ||
for (const [key, value] of Object.entries(asObject)) { | ||
if (value !== null && value !== undefined) { | ||
setKeys.add(key); | ||
} | ||
} |
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Is the Set really needed? Since we are validating the object has exactly 1 key, and JS object doesn't allow multiple entries under same key, why not just Object.keys(asObject)?.length !== 1
?
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You can have multiple keys where only one is not null - { a: 1, b: null, c: null }
is a valid union (and a check of the # of keys would fail in this case, I think)
Set
isn't being used here as a way to deduplicate. I just used it because order doesn't matter and object keys are expected to be unique anyway.
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Since Object.entries
already returns a collection, it's looks unnecessary to create a Set explicitly. Will this do?
const isDefined = (value: unknow): boolean => value !== null && value !== undefined;
if (Object.values(asObject).filter(isDefined).length !== 1) {
throw new TypeError(`Unions must have exactly one non-null member`);
}
return asObject;
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I'd like to include which keys were non-null in the error message when more than one key is set, which I can't do if I just filter the values.
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The suggested way is more idiomatic. But we don't feel strong about it.
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The use of Set
seems unnecessary.
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Ship it!
Unions must be JSON objects that only have one key set.
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Re-approve
This thread has been automatically locked since there has not been any recent activity after it was closed. Please open a new issue for related bugs and link to relevant comments in this thread. |
Description
Unions must be JSON objects that only have one key set.
Testing
Unit tests, and protocol tests against regenerated clients.
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